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abruzzese [7]
2 years ago
9

A rigid tank contains 3 kg of water initially at 43.97% quality and at a temperature of 120°C. The water is heated until it reac

hes a pressure of 7 bar. Neglect changes in kinetic and potential energy.
a. At what temperature, in °C, will the water become saturated vapor?
b. Determine the heat transfer, in kJ.
c. The work of the cycle, in kJ

Engineering
1 answer:
makkiz [27]2 years ago
6 0

Explanation: see attachment below

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An angle grinder is best suited for use with which material?.
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Angle grinders are used mostly for copper, iron, steel, lead, and other metals.

Explanation:

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Voltage signals are generated on the output of a piezoelectric pressure transducer that is equipped with an amplifier.
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Answer: True

Explanation: Piezoelectric pressure transducers are equipments that helps to generate voltage through the mechanical actions such as applied pressure. Piezoelectric transducer is made up of quartz crystals which are made of silicone and oxygen formed in a crystalline structure.

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2 years ago
Rsidential Solar Solution:a. A type of photovoltaic solar panel manufactured in China receives a rating of 250W. The rating proc
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Answer:

a) \eta = 13.455\%, b) E_{day} = 812.716\,kJ, c) C_{month. total} = 19.505\, USD, d) t = 40.588\,years

Explanation:

a) The area of the solar panel is:

A = (20\,ft^{2})\cdot (\frac{0.3048\,m}{1\,ft} )^{2}

A = 1.858\,m^{2}

The energy potential is determined herein:

\dot E_{o} = (1000\,\frac{W}{m^{2}} )\cdot (1.858\,m^{2})

\dot E_{o} = 1858\,W

The efficiency of the solar panel is:

\eta = \frac{\dot E}{\dot E_{o}}\times 100\%

\eta = \frac{250\,W}{1858\,W}\times 100\%

\eta = 13.455\%

b) The energy generated by the solar panel is presented below:

E_{day} = (0.135)\cdot (150\,\frac{W}{m^{2}} )\cdot (20\,ft^{2})\cdot \left(\frac{0.3048\,m}{1\,ft} \right)^{2}\cdot (6\,h)\cdot (\frac{3600\,s}{1\,h} )\cdot (\frac{1\,kJ}{1000\,J} )

E_{day} = 812.716\,kJ

c) The energy generated per month and per panel is:

E_{month} = 30\cdot E_{day}

E_{month} = 30 \cdot (812.716\,kJ)\cdot \left(\frac{1\,kWh}{3600\,kJ}  \right)

E_{month} = 6.773\,kWh

Monthly energy savings due to the use of 18 panels are:

C_{month, total} = 18\cdot E_{month}\cdot c

C_{month, total} = 18\cdot (6.773\,kWh)\cdot (\frac{0.16\,USD}{1\,kWh} )

C_{month. total} = 19.505\, USD

d) The payback of the solar energy system is:

t = \frac{9500\,USD}{12\cdot (19.505\,USD)}

t = 40.588\,years

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