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mafiozo [28]
3 years ago
5

The dot plots below show the scores for a group of students who took two rounds of a quiz:

Mathematics
2 answers:
vodomira [7]3 years ago
8 0

Answer:

Step-by-step explanation:

Katena32 [7]3 years ago
4 0

Answer:

DO YOU STILL NEED HELP?

Step-by-step explanation:

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1. m∠QPR =<br><br> 2. m∠QTP =<br><br> 3. RP =<br> Show all the work
alex41 [277]

Answer:

1. 30°

2.90°

3. 12 units

Step-by-step explanation:

I can't believe there's nothing confirming that this is a parallelogram/a rhombus?! Assuming is awful, and I wish you could say you can't know for sure lol but for the sake of this answer, let's just call it a rhombus. (There was probably some context elsewhere that you didn't put over here, hopefully.)

1.

The reason I say this is: in a rhombus, the diagonals bisect the angles. This means that the diagonals split the angles they meet into two equal parts. That way, it would make sense. m∠QPR=m∠SPR=30°.

2.

If it is a rhombus, the diagonals are perpendicular to each other, so m∠QTP should be 90°.

3.

Diagnonals in a rhombus (and in any parallelogram) bisect each other, so PT=TR=6, and RP=PT+TR=12 units.

Sorry if this is all dreadfully wrong, and I hope I helped you!

7 0
3 years ago
1.How many combinations are possible from the letters HOLIDAY if the letters are taken?
Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

Exercise 1, item a:

One letter from a set of 7, hence:

C_{7,1} = \frac{7!}{1!6!} = 7

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

C_{7,2} = \frac{7!}{2!5!} = 21

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

C_{7,7} = \frac{7!}{0!7!} = 1

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

6 0
2 years ago
Out of a 49 inch piece of ribbon, how many 3.5 inch pieces can Sally cut
Zolol [24]

14. You divide the length of ribbon by the size of the pieces wanted so you get

49/3.5 = 14

8 0
3 years ago
Joe is building a fort for his little brother out of boxes. He is wondering how much room there will be inside the fort.
Levart [38]
The answer is 0.5m cubed.
8 0
3 years ago
Hey :)
Slav-nsk [51]
Vertex = (3, 5)
focus = (3, 7)
directrix is y = 3
8 0
3 years ago
Read 2 more answers
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