There are following layers in earth atmosphere
a) Troposhere: the innermost layer or lowest part of atmosphere
b)stratosphere: next to troposhere
c)mesosphere:above stratosphere, here lowest temperature is observed
d)Thermosphere and Ionosphere: This layer allows long distance radio communication
e)Exosphere: this layer separates outer space from earth's surface.
Answer:
c. 15 g Kr
Explanation:
The amount of a gas (Moles) is directely proportional to its pressure. That means the higher amount of moles, the highest pressure and vice versa.
Using molar mass of the compounds (Ne=20.2g/mol, Ar = 39.9g/mol, Kr = 83.8g/mol, CO₂ = 44 g/mol and F₂ = 38.0g/mol), moles of 15.0g of each gas are:
Ne = 15g ₓ (1mol / 20.2g) = <em>0.74 moles of Ne</em>
Ar = 15g ₓ (1mol / 39.9g) = <em>0.38 moles of Ar</em>
Kr = 15g ₓ (1mol / 83.8g) = <em>0.18 moles of Kr</em>
CO₂ = 15g ₓ (1mol / 44g) = <em>0.34 moles of CO₂</em>
F₂ = 15g ₓ (1mol / 38g) = <em>0.39 moles of F₂</em>
<h3>As 15g of Kr contains the less quantity of moles, this sample will con have the lowest pressure</h3>
Hi. 2fouls! :)
First convert the number from kilometer to miles:
Now to find the miles per minutes,divide the miles per hours by 60 (the amount of minutes in an hour.)
The car is travelling at a speed of 0.860766667 miles/minute.
Hope this helps.
-Benjamin
Answer:
Option A. 70.0 KPa.
Explanation:
Data obtained from the question include:
Pressure (torr) = 525.4 torr
Pressure (kPa) =?
The pressure expressed in torr can be converted kPa as shown below:
760 torr = 101.325 KPa
Therefore,
525.4 torr = (525.4 x 101.325) / 760 = 70.0 KPa.
Therefore, 525.4 torr is equivalent to 70.0 KPa.
