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IRINA_888 [86]
3 years ago
10

Define Kinetic Energy:

Physics
2 answers:
mrs_skeptik [129]3 years ago
7 0

Answer:

kinetic energy is the energy an object has beause of it's motion

yawa3891 [41]3 years ago
4 0

Answer:

See explanation below

Explanation:

Kinetic energy is energy stored in a moving object.

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The moon has a mass of 7.34 . 102 kg and a radius of 1.74 . 106 meters. If you have a mass of 66 kg,
Ierofanga [76]

Answer:

F=1.06\times 10^{-18}\ N

Explanation:

Given that,

Mass of the Moon, M=7.34\times 10^2\ kg

Mass of the person, m = 66 kg

The radius of Moon, r=1.74\times 10^6\ m

We need to find the force between the person and the Moon. The formula for the gravitational force is given by :

F=G\dfrac{Mm}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{7.34\times 10^2\times 66}{(1.74\times 10^6)^2}\\\\=1.06\times 10^{-18}\ N

So, the required force is 1.06\times 10^{-18}\ N.

3 0
3 years ago
Is jacob barnes a turd face?
aleksandrvk [35]
Yes everyone knows this
3 0
3 years ago
Read 2 more answers
Kyle, a 95.0 kg football player, leaps straight up into the air (with no horizontal velocity) to catch a pass. He catches the 0.
babymother [125]

Answer:

The initial speed of the ball was 26.2 m/s

Explanation:

When the football player is in the air at his maximum height the vertical component of velocity is zero, To obtain the horizontal velocity when the player catches the ball we need to apply the linear momentum conservation theorem:

m_1*v_{o1}+m_2*v_{o2}=m_t*v_f\\0.430kg*(v)+m_2*(0)=mt*vt

we need to obtain the time taken to go down.

y=Y_o+v_o*t-\frac{1}{2}g*t^2\\\\0=0.589-4.9t^2\\solving:\\t_1=0.346s\\

We have a horizontal displacement and the time taken to stop, so:

v_f=\frac{d}{t}=\frac{0.0409m}{0.346s}=0.118m/s

so:

0.430kg*(v)+m_2*(0)=(m1+m2)*vt\\v=\frac{(95.0kg+0.430kg)*0.118m/s}{0.430kg}\\\\v=26.2m/s

8 0
3 years ago
A. Which of the four thermal processes describes the pressure-volume relationship at a constant temperature?
zhannawk [14.2K]
Boyles law describes pressure volume relationship at constant temperature  pressure is directly proportional  to volume at constant tamparature
4 0
3 years ago
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A 5.45-g combustible sample is burned in a calorimeter. the heat generated changes the temperature of 555 g of water from 20.5°c
Y_Kistochka [10]
Given:
m = 555 g, the mass of water in the calorimeter
ΔT = 39.5 - 20.5 = 19 °C, temperature change
c = 4.18 J/(°C-g), specific heat of  water

Assume that all generated heat goes into heating the water.
Then the energy released is
Q = mcΔT
    = (555 g)*(4.18 J/(°C-g)*(19 °C)
    = 44,078.1 J
    = 44,100 J (approximately)

Answer:  44,100 J

3 0
3 years ago
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