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chubhunter [2.5K]
4 years ago
7

Consider the metal cesium, whose atoms are 0.265 nanometers in radius (for metallic bonds) ... the largest of all the elements.

What is the length, in nanometers, of the empty space between atoms that reside along <100> directions in a BCC crystal of Cs metal?
Physics
1 answer:
larisa86 [58]4 years ago
8 0

Answer:

The edge length of the empty space between atoms that reside along [100] directions in a BCC crystal of Cs metal is 0.612 nanometers

Explanation:

For Body centered cubic structure (BCC) crystal in direction [100], the edge length of unit cell is calculated with the formula below;

X = \frac{4R}{\sqrt{3}}

Where;

X is the edge length of the empty space between atoms

R is the radius of the cesium atom = 0.265 nanometers

X = (4*0.265)/(√3)

X = 0.612 nanometers

Therefore, the edge length of the empty space between atoms that reside along [100] directions in a BCC crystal of Cs metal is 0.612 nanometers

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The correct answer is <u>B. Where crust is destroyed.</u>

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A spin balancer rotates the wheel of a car at 480 revolutions per minute. if the diameter of the wheel is 26 inches, what road s
Mariana [72]
Part A:
To answer this item, we need to convert the given revolutions per minute in speed expressed as miles per hour. In order to do so, we need to use the dimensional analysis and the appropriate conversion factor.
 
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     C = πD
where C is the circumference and D is the diameter.

Substitute the known values,
       C = π(26 in) = 81.68 inches

The speed tested is calculated below.
      s = (81.68 inches/rev)(480 rev/min)(1 mil/63360 inches)(60 min/1 hr)
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<em>ANSWER: 37.127 mil/h</em>

Part B:
Similar to what was done in Part A, the setting of the balancer is calculated below,
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3 0
3 years ago
2. A 1.54 kΩ resistor is connected to an AC voltage source with an rms voltage of 240 V.
svp [43]

(a) The maximum potential difference across the resistor is 339.41 V.

(b) The maximum current through the resistor is 0.23 A.

(c) The rms current through the resistor is 0.16 A.

(d)  The average power dissipated by the resistor is 38.4 W.

<h3>Maximum potential difference</h3>

Vrms = 0.7071V₀

where;

  • V₀ is peak voltage

V₀ = Vrms/0.7071

V₀ = 240/0.7071

V₀ = 339.41 V

<h3> rms current through the resistor </h3>

I(rms) = V(rms)/R

I(rms) = (240)/(1,540)

I(rms) = 0.16 A

<h3>maximum current through the resistor </h3>

I₀ = I(rms)/0.7071

I₀ = (0.16)/0.7071

I₀ = 0.23 A

<h3> Average power dissipated by the resistor</h3>

P = I(rms) x V(rms)

P = 0.16 x 240

P = 38.4 W

Learn more about maximum current here: brainly.com/question/14562756

#SPJ1

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2 years ago
PLEASE HELP QUICK
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Answer:

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