To Find :
Number of moles of C₃H₆O present in a sample weighing 25.6 grams.
Solution :
Molecular mass of C₃H₆O is :
M = (6×12) + (6×1) + (16×1) grams
M = 94 grams/mol
We know, number of moles of 25.6 grams of C₃H₆O is :

Hence, this is the required solution.
Answer:
The pH in 0.140 M hippuric acid solution is 2.2.
Explanation :
Dissociation constant of the acid = 
![pK_a=-\log[K_a]](https://tex.z-dn.net/?f=pK_a%3D-%5Clog%5BK_a%5D)
![3.62=-\log[K_a]](https://tex.z-dn.net/?f=3.62%3D-%5Clog%5BK_a%5D)

Concentration of hippuric acid = c = 0.140 M

Initially
c 0 0
At equilibrium
(c-x) x x
Concentration of acid = c ![[HC_9H_8NO_3]=0.140 M](https://tex.z-dn.net/?f=%20%5BHC_9H_8NO_3%5D%3D0.140%20M)
Dissociation constant of an acid is given by:
![K_a=\frac{[C_9H_8NO_{3}^-][H^+]}{[HC_9H_8NO_{3}]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BC_9H_8NO_%7B3%7D%5E-%5D%5BH%5E%2B%5D%7D%7B%5BHC_9H_8NO_%7B3%7D%5D%7D)


Solving for x:
x = 0.005677 M
![[H^+]=x = 0.005677 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dx%20%3D%200.005677%20M)
The pH of the solution :
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
![pH=-\log[0.005677 M]=2.246\approx 2.2](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B0.005677%20M%5D%3D2.246%5Capprox%202.2)
The pH in 0.140 M hippuric acid solution is 2.2.
The answer is an acid.
That is a substance that gives up a proton during a chemical reaction, raising the hydrogen ion concentration of water, is most appropriately called an acid.
Acid is a substance that gives protons in its aqueous solution, and that the hydrogen ion concentration of that aqueous solution .
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