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anzhelika [568]
4 years ago
15

How many atoms are in 45.6 g gold, Au

Chemistry
1 answer:
Gemiola [76]4 years ago
5 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

45.6 g Au ( 1 mol / 196.97 g ) (  </span>6.022 x 10^23 atoms / mole ) = 1.39x10^23 atoms Au
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Calculate the adjusted retention times for both pentafluorobenzene and benzene if the elution time for unretained solute is 1.06
vovangra [49]

Answer:

Pentafluorobenzene: 11,92 min

Benzene: 12,14 min

Explanation:

<em>Retention time of pentafluorobenzene is 12,98 min and 13,20 min of benzene.</em>

The adjusted retention time is the time an analyte spends in the column not the stationary phase. As time of unretained solute is 1,06 min the adjusted retention time for an analyte is:

tr' = tr - 1,06min

For pentafluorobenzene:

tr' = 12,98min - 1,06min = <em>11,92 min</em>

For benzene:

tr' = 13,20 - 1,06min = <em>12,14 min</em>

<em></em>

I hope it helps!

3 0
3 years ago
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const2013 [10]
A is the answer to the question you asked.
7 0
3 years ago
When salt dissolves in water, the water molecules are attracted by dissolves salt particles. This attraction is called ?
Elza [17]

When salt dissolves in water, the water molecules are attracted by dissolves salt particles. This attraction is called dissociation.

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4 0
3 years ago
Standardization is the process of titrating a solution prepared from
Zolol [24]

Answer:

Standardization is the process of titrating a solution prepared from a carefully measured mass of solid accurately determine the concentration of the titrant.

6 0
3 years ago
Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sampl
Ugo [173]

0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.

Explanation:

Data given:

Volume of the base = 47 ml

molarity of the base= 0.39 M

volume of the acid = 25 ml

molarity of the acid =?

For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined.  The formula used:

Macid X Vacid = Vbase x Mbase

Macid = \frac{Vbase X M base}{V acid}

putting the values given in the rearranged equation above:

Macid = \frac{0.39 x47}{25}

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The concentration of the sulphuric acid needed is 0.73 M.

3 0
3 years ago
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