1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anzhelika [568]
3 years ago
15

How many atoms are in 45.6 g gold, Au

Chemistry
1 answer:
Gemiola [76]3 years ago
5 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

45.6 g Au ( 1 mol / 196.97 g ) (  </span>6.022 x 10^23 atoms / mole ) = 1.39x10^23 atoms Au
You might be interested in
Please help..... who is up for a zoom to help me with balancing equations ​
Alex787 [66]

Answer:

Um I can help but not on zo.om. I can help u on here just post ur question and I will answer it

8 0
3 years ago
Read 2 more answers
Identify the situation where work is being done. Carrying a box of crayons across the room. Lifting a backpack off the floor Hol
Likurg_2 [28]
Lifting the backpack off the floor. Force is being applied in only one direction then (up) which is what constitutes as work. Carrying the box of crayons applies force in two directions (up and forward), which cancel each other out. Work has a vector, which is a quantity containing both direction and magnitude (one, finite direction, not two).
7 0
3 years ago
Read 2 more answers
4. Determine what elements are in the following compounds.
lilavasa [31]
Nitrogen=2, Hydrogen=8, Carbon=1, Oxygen=3

Hydrogen=4, Carbon=2, Oxygen=2

Iron=1, Nitrogen=2, Oxygen=6
8 0
3 years ago
In an experiment to study the photoelectric effect, a scientist measures the kinetic energy of ejected electrons as afunction of
crimeas [40]

Answer:

a) v₀ = 4.41 × 10¹⁴ s⁻¹

b) W₀ = 176 KJ/mol of ejected electrons

c) From the graph, light of frequency less than v₀ will not cause electrons to break free from the surface of the metal. Electron kinetic energy remains at zero as long as the frequency of incident light is less than v₀.

d) When frequency of the light exceeds v₀, there is an increase of electron kinetic energy from zero steadily upwards with a constant slope. This is because, once light frequency exceeds, v₀, its energy too exceeds the work function of the metal and the electrons instantaneously gain the energy of incident light and convert this energy to kinetic energy by breaking free and going into motion. The energy keeps increasing as the energy and frequency of incident light increases and electrons gain more speed.

e) The slope of the line segment gives the Planck's constant. Explanation is in the section below.

Explanation:

The plot for this question which is attached to this solution has Electron kinetic energy on the y-axis and frequency of incident light on the x-axis.

a) Wavelength, λ = 680 nm = 680 × 10⁻⁹ m

Speed of light = 3 × 10⁸ m/s

The frequency of the light, v₀ = ?

Frequency = speed of light/wavelength

v₀ = (3 × 10⁸)/(680 × 10⁻⁹) = 4.41 × 10¹⁴ s⁻¹

b) Work function, W₀ = energy of the light photons with the wavelength of v₀ = E = hv₀

h = Planck's constant = 6.63 × 10⁻³⁴ J.s

E = 6.63 × 10⁻³⁴ × 4.41 × 10¹⁴ = 2.92 × 10⁻¹⁹J

E in J/mol of ejected electrons

Ecalculated × Avogadros constant

= 2.92 × 10⁻¹⁹ × 6.023 × 10²³

= 1.76 × 10⁵ J/mol of ejected electrons = 176 KJ/mol of ejected electrons

c) Light of frequency less than v₀ does not possess enough energy to cause electrons to break free from the metal surface. The energy of light with frequency less than v₀ is less than the work function of the metal (which is the minimum amount of energy of light required to excite electrons on metal surface enough to break free).

As evident from the graph, electron kinetic energy remains at zero as long as the frequency of incident light is less than v₀.

d) When frequency of the light exceeds v₀, there is an increase of electron kinetic energy from zero steadily upwards with a constant slope. This is because, once light frequency exceeds, v₀, its energy too exceeds the work function of the metal and the electrons instantaneously gain the energy of incident light and convert this energy to kinetic energy by breaking free and going into motion. The energy keeps increasing as the energy and frequency of incident light increases and electrons gain more speed.

e) The slope of the line segment gives the Planck's constant. From the mathematical relationship, E = hv₀,

And the slope of the line segment is Energy of ejected electrons/frequency of incident light, E/v₀, which adequately matches the Planck's constant, h = 6.63 × 10⁻³⁴ J.s

Hope this Helps!!!

5 0
3 years ago
At what temperature scale Fahrenheit shows double than Kelvin scale​
sergij07 [2.7K]

Answer:

-12.3 degrees F.

Originally Answered: At what temperature does the Kelvin scale read double the Fahrenheit reading? -24.6 degrees C = -12.3 degrees F.

Explanation:

8 0
3 years ago
Other questions:
  • What solution is placed when plating metal with gold?
    10·2 answers
  • A weak bond called a ______ bond results from an attraction between a slightly positive region in a molecule and a slightly nega
    13·1 answer
  • Please hurry I’m stuck!!
    11·2 answers
  • Every element has a unique amount of
    8·1 answer
  • Oblicz masę tlenu, wiedząc, że wypełnia on pomieszczenie o rozmiarach 2m x 3.5m x 3m. Gęstość tlenu wynosi 1,249kg/m3 .
    7·1 answer
  • A student pours 800.0 mL of a 3.000 molar solution of sodium hydroxide into a 2.00 liter volumetric flask and fills the flask up
    8·1 answer
  • What would you do during a zombie apocalipse
    7·1 answer
  • I What<br>What is ment by<br>ment by covalency?​
    5·1 answer
  • Mass of 4.50 moles of oxygen gas. Answer with 3 significant digits
    8·1 answer
  • The chemical equation below shows the photosynthesis reaction. 6co2 6h2o right arrow. c6h12o6 6o2 the molar mass of carbon dioxi
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!