0.0006 in scientific notation is 6 × 10-4
<h2>Step by step Explanation:</h2>
All numbers in scientific notation or standard form are written in the form
m × 10n, where m is a number between 1 and 10 ( 1 ≤ |m| < 10 ) and the exponent n is a positive or negative integer.
To convert 0.0006 into scientific notation, follow these steps:
Move the decimal 4 times to right in the number so that the resulting number, m = 6, is greater than or equal to 1 but less than 10
Since we moved the decimal to the right the exponent n is negative
n = -4
Write in the scientific notation form m × 10n
= 6 × 10-4
Therefore,
6 × 10-4 is the scientific notation form of 0.0006 number and 6e-4 is the scientific e-notation form for 0.0006
<h2>HOPE IT HELPS ☺️</h2>
Answer:
Less soil erosion
Explanation:
Due to the low amount of rainfall in this region, it is easier to say that the region compared to other ecoregion will suffer less soil erosion.
Erosion is usually the washing away of the top layer of the soil. Rainfall is one of the most important element that causes erosion. Surface runoff for an extended period of time can remove the topmost layer of the earth on which plant can grow. This starves the soil of its rich nutrients and minerals.
Answer:
The correct answer to the following question will be "NaCl".
Explanation:
- A solute is being known as the soluble material within a liquid or a solution. The solvent is available in larger quantities than those of the solute among fluid.
- Concentration seems to be a calculation including its quantity of solvent contained in such a liquid solution, regard to something like the solvent volume.
So that NaCl is the right answer.
Answer:
Explanation:
In this problem,
we will determine the enthalpy at the end of heat input and we get the condition is the super heated state.
so the entropy change will be due to latent heat at 150 kPa and also due to temperature change at the super heated state.
All the temperature, enthalpy is evaluated with the help of the steam table.
mass is calculated with the help of a specific volume at initial condition.
<u>see image below</u>
