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2 years ago

1. ¿Qué entendemos por laalquimia y los iatroquimica(Paracelso)?

1 answer:

4 0

El concepto de iatroquímica se refiere a una etapa histórica de la química como ciencia, cuando comenzaba a despegarse de la alquimia y se vinculaba a la medicina. ... Fue Paracelso quien sostuvo que los procesos fisiológicos y patológicos eran causados por reacciones químicas.

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What is an example of a cold current

Sergeu [11.5K]

Answer:

up draft of air

Explanation:

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3 years ago

How much heat is required to raise the temperature of 475 grams of solid aluminum from room temperature (295k) to liquid aluminu

Rzqust [24]

295k=22°c
1050k=777°

total heat needed=
(0.475)(777-22)(specific heat capacity of aluminium)+(0.475)(specific latent heat of aluminium)

7 0

3 years ago

My test is tomorrow and I'm confused about how to solve these. pls halp

Stels [109]

Answer:

Explanation:

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2 years ago

The reaction between SO2 and O2 to give SO3 was studied to determine the rate law for the reaction. The following results were o

Tom [10]

Answer : (b) The rate law expression for the reaction is:

$\text{Rate}=k[SO_2]^2[O_2]$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The general reaction is:

$A+B\rightarrow C+D$

The general rate law expression for the reaction is:

$\text{Rate}=k[A]^a[B]^b$

where,

a = order with respect to A

b = order with respect to B

R = rate law

k = rate constant

$[A]$ and $[B]$ = concentration of A and B reactant

Now we have to determine the rate law for the given reaction.

The balanced equations will be:

$2SO_2+O_2\rightarrow 2SO_3$

In this reaction, $SO_2$ and $O_2$ are the reactants.

The rate law expression for the reaction is:

$\text{Rate}=k[SO_2]^2[O_2]^1$

or,

$\text{Rate}=k[SO_2]^2[O_2]$

8 0

3 years ago

Be sure to answer all parts. A 0.365−mol sample of HX is dissolved in enough H2O to form 835.0 mL of solution. If the pH of the

Marta_Voda [28]

Answer:

The Ka is 9.11 *10^-8

Explanation:

Step 1: Data given

Moles of HX = 0.365

Volume of the solution = 835.0 mL = 0.835 L

pH of the solution = 3.70

Step 2: Calculate molarity of HX

Molarity HX = moles HX / volume solution

Molarity HX = 0.365 mol / 0.835 L

Molarity HX = 0.437 M

Step 3: ICE-chart

[H+] = [H3O+] = 10^-3.70 = 1.995 *10^-4

Initial concentration of HX = 0.437 M

Initial concentration of X- and H3O+ = 0M

Since the mole ratio is 1:1; there will react x M

The concentration at the equilibrium is:

[HX] = (0.437 - x)M

[X-] = x M

[H3O+] = 1.995*10^-4 M

Since 0+x = 1.995*10^-4 ⇒ x=1.995*10^-4

[HX] = 0.437 - 1.995*10^-4 ≈ 0.437 M

[X-] = x = 1.995*10^-4 M

Step 4: Calculate Ka

Ka = [X-]*[H3O+] / [HX]

Ka = ((1.995*10^-4)²)/ 0.437

Ka = 9.11 *10^-8

The Ka is 9.11 *10^-8

4 0

3 years ago

1. ¿Qué entendemos por laalquimia y los iatroquimica(Paracelso)?​

1. ¿Qué entendemos por laalquimia y los iatroquimica(Paracelso)?