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zlopas [31]
3 years ago
13

Water molecules have a strong attraction to each other because of hydrogen bonding, allowing water to move against gravity up a

plant's stem through capillary action. True False
Chemistry
2 answers:
ohaa [14]3 years ago
8 0
The answer would be true
Valentin [98]3 years ago
6 0
The answer to that question is true
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15g of magnesium (II) oxide decomposes, find the number of oxygen particles produced at 100% yield.
erastova [34]

2.258625 *10²³ oxygen atoms will be produced.

<h3><u>Explanation:</u></h3>

Decomposition reaction is defined as the type of reaction where one single reactant breaks to produce more than one product only by means of heat or other external factor.

Formula of magnesium oxide = MgO.

The molecular mass of magnesium oxide = 24 +16= 40.

So in 40 grams of magnesium oxide, number of molecules is 6.023 * 10²³.

So in 15 grams of magnesium oxide,, number of molecules is 6.023 *1023 * 15/40 = 2.258625 *10²³.

From one molecule of magnesium oxide, one oxide atom will be produced.

So number of oxide atoms with 100% yeild = 2.258625 *10²³

6 0
3 years ago
The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:
ololo11 [35]

The allowable combination for the atomic orbital is n=3, l=1 or 2, m_{l}=+1.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; m_{l} values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Hence, the l value must be lower than 3. Because of m_{l}= +1, the l value must be higher than 0. Two l values are consistent with n and m_{l) values:

l= 1 or 2

Therefore, the allowable condition is n=7, l=1 or 2, m_{l}=+3.

To know more about quantum numbers, visit: brainly.com/question/16979660

#SPJ4

7 0
1 year ago
When a compound donates (loses) electrons, that compound becomes oxidized. Such a compound is often referred to as an electron d
rjkz [21]

Assuming this is a true or false question, the answer would be True

3 0
2 years ago
Calculate the grams of ethane present in a sample containing 0.8286 moles if the molar mass of ethane is 30.067 g/mol.
BlackZzzverrR [31]
N = m/M

Where,

n = number of moles

m = mass of substance

M = molar mass of substance

0.8286 = m / 30.067

Multiply both sides by 30.067

m = 24.9135162g




5 0
2 years ago
Given a chemical reaction, methane (CH4) burns in oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). Which of these re
kicyunya [14]
A; methane and oxygen are reactants, carbon dioxide and water are products
7 0
3 years ago
Read 2 more answers
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