The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:
1 answer:
The allowable combination for the atomic orbital is n=3, l=1 or 2, =+1.
Three quantum numbers specify an atomic orbital:
- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.
- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),
- is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus;
values are integers from -l to =l(l limits ml)
For n = 3, l can have three values: 0, 1, and 2. Hence, the l value must be lower than 3. Because of = +1, the l value must be higher than 0. Two l values are consistent with n and
values:
l= 1 or 2
Therefore, the allowable condition is n=7, l=1 or 2, =+3.
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Answer:
See explanation.
Explanation:
Hello,
In this case, we could have two possible solutions:
A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:
That is the mass of copper (II) sulfate contained in 1 mol of substance.
B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:
So you can solve for the moles of the solute:
Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:
But this is just a supposition.
Regards.