Question

The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:

Answer 1

The allowable combination for the atomic orbital is n=3, l=1 or 2, $m_{l}$=+1.

What are the three quantum numbers of an atomic orbital?

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; $m_{l}$ values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Hence, the l value must be lower than 3. Because of $m_{l}$= +1, the l value must be higher than 0. Two l values are consistent with n and $m_{l)$ values:

l= 1 or 2

Therefore, the allowable condition is n=7, l=1 or 2, $m_{l}$=+3.

To know more about quantum numbers, visit: brainly.com/question/16979660

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