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3 years ago

The experimental group is the group that is left alone during the experiment

Chemistry

1 answer:

Paladinen [302]3 years ago

4 0

Answer:

The given statement is false.

Explanation:

A common method of experimentation that is used to collect data on hypotheses of end up causing-effect is a contrast between two groups.
One community, the experimental group, is receiving medication for having any result. Some other group becomes left exposed, the control group, whether creating a different treatment.

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Calculate the amount of carbon dioxid gas in 1.505x10^23 molecules of the gas.

Daniel [21]

Explanation:

We need to find the amount of carbon dioxide gas in $1.505\times 10^{23}$ molecules of the gas.

We know that, 1 mole weighs 44 gram of carbon dioxide which contains $6.022\times 10^{23}$ number of molecules. It means that, $6.022\times 10^{23}$ number of molecules present in 44 grams of carbon dioxide molecule. So, $1.505\times 10^{23}$ number of molecules present in :

$=\dfrac{1.0505\times 10^{23}}{6.022\times 10^{23}}\times 44\\\\=7.675\ \text{grams}$

Hence, 7.675 grams of carbon dioxide is present in $1.505\times 10^{23}$ molecules of the gas.

4 0

3 years ago

A pH of 2 indicates a(n) _____.

solniwko [45]

A pH of 2 indicates a acid

6 0

3 years ago

On the electromagnetic spectrum what two types of waves are microwaves between?

boyakko [2]

Microwaves are defined as electromagnetic radiations with a frequency ranging between 300 MHz to 300 GHz while the wavelength ranges from 1 mm to around 30 cm. The microwave radiation is commonly referred to as microwaves. They fall between the infrared radiation and radio waves in the electromagnetic spectrum. radio waves in the electromagnetic spectrum.

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3 years ago

Menstruation occurs on a ______ interval from puberty until menopause

dmitriy555 [2]

D. One Month Interval

8 0

3 years ago

Calculate the pOH of a 0.0143 M NaOH solution at 25 ⁰C.

arsen [322]

Answer:

A.) 1.845

Explanation:

You can find the pOH using the following equation:

pOH = -log[OH⁻]

Since NaOH dissociates into 1 Na⁺ and 1 OH⁻, the concentration of both ions is 0.0143 M.

pOH = -log[OH⁻]

pOH = -log[0.0143]

pOH = 1.845

5 0

2 years ago