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3 years ago

Please help me I’m not sure with that

Chemistry

2 answers:

Tems11 [23]3 years ago

8 0

Answer:

i cant see the picture sorry

Explanation:

Alex73 [517]3 years ago

5 0

What I can’t see the pic ?hhbc639l73773 ghcbhjbch

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Counting atoms worksheet answer key i need help!!

katovenus [111]

Answer is in a pho $^{}$ to. I can only uplo $^{}$ ad it to a file host $^{}$ ing service. link below!

bit. $^{}$ ly/3a8Nt8n

6 0

3 years ago

A quantity of water is heated from 25.0°C to 36.4°C by absorbing 325 J of heat energy. If the specific heat of water is 4.18 J /

Arlecino [84]

Answer:

6,8 g

Explanation:

c = 4.18 J/(g * °C) = 4180 J / (kg * °C)

$t_{1}$ = 25 °C

$t_{2}$ = 36,4 °C

Q = 325 J

The formula is: Q = c * m * ( $t_{2} - t_{1}$ )

m = $\frac{Q}{c * (t_{2} - t_{1} )}$

Calculating:

m = 325 / 4180 * (36,4 - 25) ≈ 0,0068 kg = 6,8 g

6 0

3 years ago

Pls it’s urgent

Rainbow [258]

Answer:

0.02 moles.

Explanation:

volume of H₂ gas at R.T.P = 480 cm³

Where

R.T.P = room temperature and pressure

molar volume of gas at = 24000 cm³

no. of moles of hydrogen = ?

Solution:

formula Used

no. of moles = volume of gas / molar volume

put values in above equation

no. of moles = 480 cm³ / 24000 cm³/mol

no. of moles = 0.02 mol

So,

no. of moles of hydrogen in 480 cm³ is 0.02 moles.

4 0

3 years ago

imagine you are a particle of air explain your journey in the atmosphere as you beacome a heated particle if you answer it clear

enyata [817]

Well when a particle of air is becomes heated it rises, right? So you could write some like you started off close to the earth (aka the troposphere) until you became heated then you started to rise and as you reached higher elevations you cooled down and you were recycled into cool air and you moved back down and became new fresh cool air until the next time you'll become heated and rise again to be recycled into fresh cool new air.

6 0

3 years ago

Gallium has two naturally occurring isotopes: 69ga with a mass of 68.9256 amu and a natural abundance of 60.11% and 71ga. use th

Nataly [62]

There are two naturally occurring isotopes of gallium: mass of Ga-69 isotope is 68.9256 amu and its percentage abundance is 60.11%, let the mass of other isotope that is Ga-71 be X, the percentage abundance can be calculated as:

%Ga-71=100-60.11=39.89%

Atomic mass of an element is calculated by taking sum of atomic masses of its isotopes multiplied by their percentage abundance.

Thus, in this case:

Atomic mass= m(Ga-69)×%(Ga-69)+X×%(Ga-71)

From the periodic table, atomic mass of Ga is 69.723 amu.

Putting the values,

$69.723 amu=(68.9256 amu)(\frac{60.11}{100})+X(\frac{39.89}{100})$