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garri49 [273]
3 years ago
6

The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample

is measured to be 0.596 times the Carbon-14 activity of living plants. What is the age of the sample in years? (The half-life of the Carbon-14 isotope is 5730 years.)
Physics
1 answer:
Bond [772]3 years ago
4 0

Answer:

4276.98 years

Explanation:

t = age of the sample in numbers of years

T = half life of the carbon-14 isotope = 5730 yrs

λ = decay constant of carbon-14

decay constant is given as

\lambda =\frac{0.693}{T}

\lambda =\frac{0.693}{5730}

\lambda = 0.000121

A₀ = activity of Carbon-14 in living plants

A  = activity of Carbon-14 after time "t" = (0.596) A₀

Using the equation

A = A_{o} e^{-\lambda t}

(0.596) A₀  = A_{o} e^{-0.000121 t}

0.596 = e^{-0.000121 t}

t = 4276.98 years

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Answer:

0.36 A.

Explanation:

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Resistor 1 (R₁) = 35 Ω

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Since, the two resistors are in parallel connections, their equivalence can be obtained as follow:

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Rₑq = (35 × 20) / (35 + 20)

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Next, we shall determine the total resistance in the circuit. This can be obtained as follow:

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R = 12.73 + 15

R = 27.73 Ω

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Total resistance (R) = 27.73 Ω

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I = 10 / 27.73

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6 0
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inn [45]

Answer:

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Explanation:

Given that:

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