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insens350 [35]
1 year ago
15

Part 1. A chemist reacted 15.0 liters of F2 gas with NaCl in the laboratory to form Cl2 and NaF. Use the ideal gas law equation

to determine the mass of NaCl that reacted with F2 at 280. K and 1.50 atm.
F2 + 2NaCl → Cl2 + 2NaF


Part 2. Explain how you would determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP.


explain please (for 40 pts)
Chemistry
1 answer:
xeze [42]1 year ago
4 0

Answer:

113 g NaCl

Explanation:

The Ideal Gas Law equation is:

PV = nRT

In this equation,

    > P = pressure (atm)

    > V = volume (L)

    > n = number of moles

    > R = 8.314 (constant)

    > T = temperature (K)

The given values all have to due with the conditions fo F₂. You have been given values for all of the variables but moles F₂. Therefore, to find moles F₂, plug each of the values into the Ideal Gas Law equation and simplify.

(1.50 atm)(15.0 L) = n(8.314)(280. K)

2250 = n(2327.92)

0.967 moles F₂ = n

Using the Ideal Gas Law, we determined that the moles of F₂ is 0.967 moles. Now, to find the mass of NaCl that can react with F₂, you need to (1) convert moles F₂ to moles NaCl (via the mole-to-mole ratio using the reaction coefficients) and then (2) convert moles NaCl to grams NaCl (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).

1 F₂ + 2 NaCl ---> Cl₂ + 2NaF

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl): 58.44 g/mol

0.967 moles F₂        2 moles NaCl             58.44 g
----------------------  x  -----------------------  x  -----------------------  =  113 g NaCl
                                     1 mole F₂              1 mole NaCl

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How many moles of ammonia, NH,, are contained in<br><br> 6.21 x 1024 molecules of ammonia?
ankoles [38]

Answer:

10.32 moles of ammonia NH₃

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 6.21×10²⁴ molecules

Number of mole of NH₃ =?

The number of mole of NH₃ can be obtained as follow:

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole

Therefore,

6.21×10²⁴ molecules = 6.21×10²⁴ / 6.02×10²³

6.21×10²⁴ molecules = 10.32 moles

Thus, 6.21×10²⁴ molecules contains 10.32 moles of ammonia NH₃

6 0
3 years ago
weather balloon is filled with helium to a volume of 340 L at 30 ∘C and 751 mmHg . The balloon ascends to an altitude where the
valentinak56 [21]

Answer: Thus the volume of the balloon at this altitude is 419 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 751 mm Hg

P_2 = final pressure of gas = 495 mm Hg

V_1 = initial volume of gas = 340 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 30^oC=273+30=303K

T_2 = final temperature of gas = -27^oC=273-27=246K

Now put all the given values in the above equation, we get:

\frac{751\times 340}{303}=\frac{495\times V_2}{246}

V_2=419L

Thus the volume of the balloon at this altitude is 419 L

8 0
3 years ago
Aspirin (C9H8O4) may be synthesized by mixing salicylic acid (C7H6O3) with excess acetic anhydride (C4H6O3).
diamong [38]

Answer:

65.18% is the percent yield for this reaction.

Explanation:

C_7H_6O_3 + C_4H_6O_3\rightarrow C_9H_8O_4 + C_2H_4O_2

Moles of salicyclic acid = \frac{2.0 g}{138 g/mol}=0.01449 mol

According to reaction 1 mole of salicyclic acid gives 1 mole of aspirin .

Then 0.01449 mole of salicylic acid will give :

\frac{1}{1}\times 0.01449 mol=0.01449 mol of asprin

Mass of 0.01449 moles of aspirin :

= 0.01449 mol × 180 g/mol = 2.6082 g

Theoretical yield of aspirin = 2.6082 g

Experimental yield of aspirin = 1.7 g

The percent yield for this reaction:

\%(Yield)=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{1.7 g}{2.6082 g}\times 100=65.18\%

65.18% is the percent yield for this reaction.

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