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insens350 [35]
2 years ago
15

Part 1. A chemist reacted 15.0 liters of F2 gas with NaCl in the laboratory to form Cl2 and NaF. Use the ideal gas law equation

to determine the mass of NaCl that reacted with F2 at 280. K and 1.50 atm.
F2 + 2NaCl → Cl2 + 2NaF


Part 2. Explain how you would determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP.


explain please (for 40 pts)
Chemistry
1 answer:
xeze [42]2 years ago
4 0

Answer:

113 g NaCl

Explanation:

The Ideal Gas Law equation is:

PV = nRT

In this equation,

    > P = pressure (atm)

    > V = volume (L)

    > n = number of moles

    > R = 8.314 (constant)

    > T = temperature (K)

The given values all have to due with the conditions fo F₂. You have been given values for all of the variables but moles F₂. Therefore, to find moles F₂, plug each of the values into the Ideal Gas Law equation and simplify.

(1.50 atm)(15.0 L) = n(8.314)(280. K)

2250 = n(2327.92)

0.967 moles F₂ = n

Using the Ideal Gas Law, we determined that the moles of F₂ is 0.967 moles. Now, to find the mass of NaCl that can react with F₂, you need to (1) convert moles F₂ to moles NaCl (via the mole-to-mole ratio using the reaction coefficients) and then (2) convert moles NaCl to grams NaCl (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).

1 F₂ + 2 NaCl ---> Cl₂ + 2NaF

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl): 58.44 g/mol

0.967 moles F₂        2 moles NaCl             58.44 g
----------------------  x  -----------------------  x  -----------------------  =  113 g NaCl
                                     1 mole F₂              1 mole NaCl

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an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m
bogdanovich [222]

Answer:

P_2=1.1x10^6Pa

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

P_1V_1=P_2V_2

In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

P_2=\frac{P_1V_1}{V_2}

Consider that the given initial pressure is also equal to Pa:

P_2=\frac{1.00x10^5Pa*11.00m^3}{1.00m^3}\\ \\P_2=1.1x10^6Pa

Which stands for a pressure increase when volume decreases.

Regards.

4 0
3 years ago
A chemist wants to make 6.5 L of a 0.340 M CaCl2 solution. Part A What mass of CaCl2 (in g) should the chemist use? Express your
katovenus [111]

Answer:

The answer to your question is 245 grams

Explanation:

Data

Volume 6.5 L

Molarity = 0.34

mass of CaCl₂ = ?

Process

1.- Calculate the molar mass of CaCl₂

molar mass = (1 x 40) + (2 x 35.5)

                   = 40 + 71

                   = 111 g

2.- Convert the grams to moles

                       111 g of CaCl₂ -------------- 1 mol

                         x                   ---------------0.34 mol

                         x = (0.34 x 111) / 1

                         x = 37.74 g

3.- Calculate the total mass

                        37.74 g ------------------ 1 L

                            x        ------------------ 6.5 L

                            x = (6.5 x 37.74) / 1

                            x = 245.31

3 0
3 years ago
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marta [7]

Answer:

295.15 i think

Explanation:

6 0
3 years ago
Warm water rising to the surface of the
White raven [17]

Answer:

convection

Explanation:

7 0
3 years ago
How many meters are present in the 12.45 miles? Please show your work, and report your answer with the correct number of signifi
MatroZZZ [7]

Explanation:

We know that,

1 mile = 1609.34 m

We need to find how many meters are present in the 12.45 miles. To find it use unitary method as follows :

12.45 mile = 1609.34 × 12.45

12.45 mile=20036.283 meters

or

12.45\ mile=2.0036\times 10^4\ m

Hence, this is the required solution.

3 0
3 years ago
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