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3 years ago

The _ contains the majority of the mass of the atom but is much than the atom.

2 answers:

6 0

A.
nucleus hold protons and neutrons that contain the mass. but is smaller due to the electron cloud making the atom bigger.

zimovet [89]3 years ago

5 0

The nucleus has almost all the mass of the atom, but only a tiny tiny tiny tiny tiny portion of the atom's volume. The rest of the atom is the electron cloud and mostly empty space. I read that the nucleus in the middle of one atom is like a bunch of grapes in the middle of Texas !

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Which equations can be used to solve for acceleration? Check all that apply.<br><br>t =

alekssr [168]

Um I would help you but I don’t see the question

8 0

3 years ago

Read 2 more answers

Calculate the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 mhz

AlekseyPX

The wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

According to the question

The frequency of a photon of electromagnetic radiation = 151.7 Mhz

By using the Formula of wavelength and frequency

λ = C/f

Where,

λ (Lambda) = Wavelength in meters

C = Speed of Light (c = 3x10⁸ m/s)

f = Frequency

Now, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is

1 Mhz = 1000000 Hz

151.7 Mhz = 151.7 * 10⁶ Hz

λ = C/f

Substituting the value of C and f

λ = $\frac{3*10^{8} }{151.7 * 10^{6} }$

λ = 1.978 meter

Hence, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

To know more about wavelength and frequency here:

brainly.com/question/18651058

#SPJ4

5 0

2 years ago

You are given aqueous solutions of six different substances and asked to determine whether they are strong, weak, or nonelectrol

kogti [31]

Answer:

Answer is explained below;

Explanation:

Electrolytes are any substances that dissociate into charged particles called ions when dissolved in water. The positively charged ions called cations and the negatively charged ions called anions move toward the negative and positive terminals (cathode and anode) of an electric circuit.

When a substance dissolved in water completely dissociates into ions, it is called a strong electrolyte. The aqueous solutions containing strong electrolytes conduct electricity very well and the examples include strong acids and soluble ionic compounds such as barium chloride, sodium hydroxide, etc.

When a substance dissolved in water does not completely dissociate into ions, it is called a weak electrolyte. Since the aqueous solutions containing weak electrolytes have relatively few ions, their electrical conductivity is very low compared to the solutions containing strong electrolytes. Examples of weak electrolytes include weak acids and bases like acetic acid, ammonia, etc.

When a substance does not dissociate into ions when dissolved in water, it is called a nonelectrolyte. Since the aqueous solutions containing nonelectrolytes do not contain any ions, such solutions do not conduct electricity. Examples of nonelectrolytes are ethanol, aldehydes, glucose, ketones, etc.

If a solution contains dissolved ions, it conducts electricity and as the ion concentration increases, the conductivity also increases. To determine whether the aqueous solutions of six different substances are strong, weak, or nonelectrolytes, we can test them by applying a voltage to electrodes immersed in the solutions and a light bulb. By observing the brightness of the light bulb or by measuring the flow of electrical current, we can find out which solution contains a strong electrolyte or weak electrolyte, or nonelectrolyte.

If the solution contains a nonelectrolyte, the current flow is nil and the light bulb does not glow. If the solution contains a strong electrolyte, the current flow is very strong and so the brightness of the light bulb is very high. If the solution contains a weak electrolyte, the current flow is much low compared to the strong electrolyte and the light bulb glows, but the brightness is very low.

3 0

4 years ago

You are driving at 35 m/s east and notice another car that is initially located 462 m in front of you and is moving east at 25 m

GaryK [48]

The easiest way to answer this question is by realizing there are relating the velocities of the two cars. To tackle this problem, you have to understand the picture. Car 1 travels at 35m/s and Car 2 travels at 25m/s. Based on relative velocities, we can understand that Car 1 travels 10m/s faster than Car 2 every second. So we can interpret Car 1's relative velocity to Car 2 as 10m/s. Car 1 needs to travel 10m/s till a point of catching up to Car 2 which is 462m away.

v = 10m/s

d = 462m

v = d/t

(10) = (462)/t

t = 46.2s

So it takes 46.2 seconds for Car 1 to catch up to Car 2, but the question is asking how far does Car 1 travel to catch up. So we have to use Car 1's velocity and not the relative velocity:

v = 35m/s

v = d/t

(35) = d/(46.2)

d = 1617m

Car 1 traveled a total distance of 1617m.

7 0

4 years ago

Read 2 more answers

In an RLC series circuit that includes a source of alternating current operating at fixed frequency and voltage, the resistance

maw [93]

Answer:

Capacitive Reactance is 4 times of resistance