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Contact [7]
3 years ago
13

The _________ contains the majority of the mass of the atom but is much ________ than the atom.

Physics
2 answers:
bulgar [2K]3 years ago
6 0
A. 
nucleus hold protons and neutrons that contain the mass. but is smaller due to the electron cloud making the atom bigger.
zimovet [89]3 years ago
5 0
The nucleus has almost all the mass of the atom, but only a tiny tiny tiny tiny tiny portion of the atom's volume. The rest of the atom is the electron cloud and mostly empty space. I read that the nucleus in the middle of one atom is like a bunch of grapes in the middle of Texas !
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The platform height for Olympic divers is 10 m. A 60 kg diver steps off the platform to begin his dive.
azamat

Answer:

a) Ep = 5886[J]; b) v = 14[m/s]; c)   W = 5886[J]; d) F = 1763.4[N]

Explanation:

a)

The potential energy can be found using the following expression, we will take the ground level as the reference point where the potential energy is equal to zero.

E_{p} =m*g*h\\where:\\m = mass = 60[kg]\\g = gravity = 9.81[m/s^2]\\h = elevation = 10 [m]\\E_{p}=60*9.81*10\\E_{p}=5886[J]

b)

Since energy is conserved, that is, potential energy is transformed into kinetic energy, the moment the harpsichord touches water, all potential energy is transformed into kinetic energy.

E_{p} = E_{k} \\5886 =0.5*m*v^{2} \\v = \sqrt{\frac{5886}{0.5*60} }\\v = 14[m/s]

c)

The work is equal to

W = 5886 [J]

d)

We need to use the following equation and find the deceleration of the diver at the moment when he stops his velocity is zero.

v_{f} ^{2}= v_{o} ^{2}-2*a*d\\where:\\d = 2.5[m]\\v_{f}=0\\v_{o} =14[m/s]\\Therefore\\a = \frac{14^{2} }{2*2.5} \\a = 39.2[m/s^2]

By performing a sum of forces equal to the product of mass by acceleration (newton's second law), we can find the force that acts to reduce the speed of the diver to zero.

m*g - F = m*a

F = m*a - m*g

F = (60*39.2) - (60*9.81)

F = 1763.4 [N]

3 0
3 years ago
Do the following calculation and express the final answer in
sammy [17]

Answer:

Explanation:

I got the same thing. So, i don't know but good luck

3 0
1 year ago
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