In the 5.12 Lab: Design a Thermos 1 (k12) HELLPPPP PLEASEEEE!!!!
1 answer:
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Answer:
<em>The car will be moving at 5.48 m/s at the bottom of the hill</em>
Explanation:
<u>Principle of Conservation of Mechanical Energy</u>
In the absence of friction, the total mechanical energy is conserved. That means that
is constant, being U the potential energy and K the kinetic energy
U=mgh
When the car is at the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.
The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.
We are given the initial potential energy U=45 J. It all is transformed to kinetic energy at the bottom of the hill, thus:
Multiplying by 2:
Dividing by m:
Taking square roots:
v = 5.48 m/s
The car will be moving at 5.48 m/s at the bottom of the hill
Answer:
The value is
Explanation:
From the question we are told that
The mass of the block is
The force constant of the spring is
The amplitude is
The time consider is
Generally the angular velocity of this block is mathematically represented as
=>
=>
Given that the block undergoes simple harmonic motion the velocity is mathematically represented as
=>
=>