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Gekata [30.6K]
4 years ago
11

To calculate changes in concentration for a system not at equilibrium, the first step is to determine the direction the reaction

will proceed. To do so, we calculate Q and compare it to the equilibrium concentration, K. We can then determine that a reaction will shift to the right if:__________
Chemistry
1 answer:
Viefleur [7K]4 years ago
3 0

Answer:

We can then determine that a reaction will shift to the right if <u><em>Q<K</em></u>

Explanation:

Comparing Q with K allows to find out the status and evolution of the system:

  • If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.
  • If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium and will evolve spontaneously, decreasing the value of Qc until it equals the equilibrium constant. In this way, the concentrations of the products will decrease and the concentrations of the reagents will increase. In other words, the reverse reaction is favored to achieve equilibrium. Then the system will evolve to the left (ie products will be consumed and more reagents will be formed).
  • If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium and will evolve spontaneously increasing the value of Qc until it equals the equilibrium constant. This implies that the concentrations of the products will increase and those of the reagents will decrease. In other words, to achieve balance, direct reaction is favored. Then the reaction will shift to the right, that is, reagents will be consumed and more products will be formed.

In this case, <u><em>we can then determine that a reaction will shift to the right if Q<K</em></u>

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In the reaction 2K + 2H2O→2KOH + H2 , which compound has an element ratio of 2:1 ?
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Option O = H₂O

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The theoretical yield of NaBr from
Lapatulllka [165]

Taking into account definition of percent yield, the percent yield for the reaction is 100%.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 FeBr₃ + 3 Na₂S → Fе₂S₃ + 6 NaBr

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • FeBr₃: 2 moles
  • Na₂S; 3 moles
  • Fе₂S₃: 1 mole
  • NaBr: 6 moles

<h3>Moles of NaBr formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 2 moles of FeBr₃ form 6 moles of NaBr, 2.36 moles of FeBr₃ form how many moles of NaBr?

moles of NaBr=\frac{2.36 moles of FeBr_{3}x6 moles of NaBr }{2 moles of FeBr_{3}}

moles of NaBr= 7.08 moles

Then, 7.08 moles of NaBr can be produced from 2.36 moles of FeBr₃.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield=\frac{actual yield}{theorical yield}x100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Percent yield for the reaction in this case</h3>

In this case, being the molar mass of NaBr 102.9 g/mole, you know:

  • actual yield= 7.08 moles× 102.9 g/mole= 728.532 grams
  • theorical yield= 7.08 moles× 102.9 g/mole= 728.532 grams

Replacing in the definition of percent yields:

percent yield=\frac{728.532 grams}{728.532 grams}x100

Solving:

<u><em>percent yield= 100%</em></u>

Finally, the percent yield for the reaction is 100%.

Learn more about

the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

percent yield:

brainly.com/question/14408642

#SPJ1

8 0
2 years ago
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