According to this formula :
㏑[A] /[Ao] = - Kt
when we have Ao = 0.3 m
and K =0.46 s^-1
t = 20min = 0.2 x 60 =12 s
So by substitution :
㏑[A] / 0.3 = - 0.46 * 12
㏑[A] / 0.3 = - 5.52
by taking e^x for both side of the equation we can get [A]
∴[A] = 0.0012 mol dm^-3
It would be most similar to neon. it wouldn’t be sulfur because that’s in the same group as oxygen and has the same number of electrons. and carbon has less than that so the only one that makes sense is neon
So the question ask on what solute are present in an aqueous solution on a certain element base on the data you have given. So base on that data i came up with a chemical expression of HCIO, H+ and CIO-. I hope you are satisfied with my answer
The element is Magnesium
- It has total 12 electrons
it has electronic configuration
or
In valence cell it has 2 electrons and therefore its valency is 2
Answer:
d. when atoms are situated in a repeating array over large atomic distances.
Explanation:
A crystalline material -
It refers to the type of solid substance where the atoms or ions are arranged in a very orderly fashion , composing a well designed lattice , is referred to as crystalline material .
These type of substances are studied under a special subtopic known as crystallography .
Hence , from the given information of the question ,
The correct option is d.
