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Anettt [7]
3 years ago
5

How many moles of solute are in 9.03 M solution with 15.8 L of solution?

Chemistry
1 answer:
balu736 [363]3 years ago
5 0

Answer:

Explanation:

How many moles of solute are in 9.03 M solution with 15.8 L of solution?

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3 years ago
How many grams of solid Ca(OH)2 (74.1 g/mol) are required to make 500 ml of a 3 M solution?
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111.15 g are required to prepare 500 ml of a 3 M solution

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In a 3 M solution of Ca(OH)₂ there are 3 moles of Ca(OH)₂ per liter solution. In 500 ml of this solution, there will be (3 mol/2) 1.5 mol Ca(OH)₂.

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(1.5 mol Ca(OH)₂ *(74.1 g / 1 mol)) 111.15 g. This mass of Ca(OH)₂ is required to prepare the 500 ml 3 M solution.

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If the volume of an object increases but the mass stays the same, which will happen to the density?
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