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3 years ago

5

Which of the following would not increase the velocity of a sound wave in air? A. lowering the humidity of the air. B. increasin

g the temperature of the air. C. increasing the wind speed in the direction the wave is traveling. D. lowering the density of the air

2 answers:

expeople1 [14]3 years ago

8 0

Answer:

Lowering the humidity of the air.

Explanation:

The mathematical formula for the speed of sound wave is given by :

$v=\sqrt{\dfrac{\gamma RT}{M}}$

Where

$\gamma$ is the adiabatic constant

T is the temperature of air

M is the molecular mass of the gas

or

$v=\sqrt{\dfrac{B}{\rho}}$

B is the bulk modulus

$\rho$ is the density of the air

As the humidity of the air increases, then the number of water molecules increase. As a result, molar mass decreases and ultimately the speed of sound increases and vice versa.

So, the correct option is (A) " lowering the humidity of the air ". Hence, this is the required solution.

Rashid [163]3 years ago

6 0

A. Lowering the humidity of the air.

Hope this helps!

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Read 2 more answers

Ilia_Sergeevich [38]

Answer:

The value is $C = 30729\ c$

Explanation:

From the question we are told that

The power rating of the stove is $P = 4.4 KW = 4.4 *10^{3} \ W$

The duration of its use everyday is $t_1 = 70 \ minutes = 1.167 \ hours$

The rating of the light bulbs is $P_2' = 150 W$

The number is $n = 7$

The power rating of the total bulb is $P_2 = 7 * 150 = 1050 \ W$

The duration of its use everyday is $t_2 = 7 hours$

The power rating of miscellaneous appliance $P_3 = 1.8 \ KW = 1.8 *10^{3} \ W$

The duration of its use everyday is $t_3 = 1 hour$

The power rating of hot water $P = 4 KW = 4 *10^{3} \ W$

The duration of its use everyday is $t_4 = 120 \ minutes = 2 hours$

Generally the total electrical energy used in 1 month is mathematically represented as

$E = P_1 * t_1 * 30 + P_2 * t_2 * 30 + P_3 * t_3 * 30+ P_4 * t_4 * 30$

=> $E = 4.4*10^{3} * 1.167 * 30 + 1050 * 7 * 30 + 1.8 *1 * 30+ 4*10^{3} * 2 * 30$

=> $E = 614598 \ W \cdot h$

=> $E = 614.6 \ K W \cdot h$

Generally the monthly electricity bill is mathematically represented as

$C = 614.6 * 50$

=> $C = 30729\ c$

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