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4 years ago

How much work is required to lift an object with a mass of 5.0 kilograms to a height of 3.5 meters?

2 answers:

7 0

Work is Force multiplied by distance: work = Fd

work = mgh

work = (5.0 kg)(9.8 m/s)(3.5 m)

work = 171.5 joules or for two sigfigs, 170 joules

Veronika [31]4 years ago

6 0

I believe it would be 172 J (or 1.72 · 10² J)

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Help pls, see picture. Will mark Brainliest

Leno4ka [110]

Answer:

Explanation:

the graph shows the line going up (accelerating) and it isn't curving like d so it doesn't stop accelerating

Hope this helps :)

4 0

3 years ago

A thin ball shell is shaped like a hollow ball with a radius of 42.8 cm. The material is a conductor with charge 0.8 nC A point

Gala2k [10]

Answer:

The Electric field will be 225.92 N/C

Explanation:

Given :

Radius of the hollow sphere R=42.8 cm
Initial charge on the conducting sphere is $Q_1=0.8\times10^{-9}\ \rm C$
Magnitude of the point charge $q_2=-5.4\times10^{-9}\ \rm C$

We know that the flux of the electric field through a close surface cab be calculated by using Gauss Law which is

$\int EdA=\dfrac{Q_{in}}{\epsilon_0}\\\\E\times4\pi\times 0.428^2=\dfrac{(0.8-5.4)\times10^{-9}}{\epsilon_0}\\\\E=225.92\ \rm N/C$

Hence the Electric Field is calculated.

The answer founded out by you seems to be correct and very close to the exact answer and the concept you have used in your answer is also correct.

5 0

3 years ago

A chunk of metal has a volume of

Alla [95]

Answer:

7213.7kg/m³

Explanation:

Given parameters:

Volume of the metal chunk = 0.131m³

Mass of the metal chunk = 945kg

Unknown:

Density of the metal chunk = ?

Solution :

To solve this problem, density is the mass per unit volume. It is mathematically expressed as;

Density = $\frac{mass}{volume}$

So;

Density = $\frac{945}{0.131}$ = 7213.7kg/m³

5 0

3 years ago

Write the equation of a wave traveling along the +x-axis with an amplitude of 0.02 m, a frequency of 440 Hz, and a speed of 330m

Airida [17]

The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)

Explanation:

Given data

Amplitude 0.02 m , Frequency= 440 Hz ,Speed = 330 m/s

The equation format is written as,

y = A sin ( k x – ω t)

We need the value of A, k, x -ω t

1. Find the k value

v = f ×λ

330 = 440×λ

k = 2π×λ

k = 880 π /330 m-1

440 ×2π = w

2. Find the ω value

f×2π =ω

ω = 880 π s-1

3. Find the A value

we get A value from the given data

A = 0.02 m

By the formula,

y = A sin ( k x – ω t)

Substitute the values we get the equation,

y = 0.02 sin (880π/330 x – 880 πt)

The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)

8 0

3 years ago

An is a heterogeneous mixture in which visible particles settle

vekshin1

Suspension should be the answer

3 0

4 years ago