Answer:
Acceleration of the car will be
Explanation:
We have given mass of the ball m = 1600 kg
Force in north direction F= 7560 N
Resistance force which opposes the movement of car
So net force on the car
According to second law of motion we know that F=ma
So
consider east-west direction along X-axis and north-south direction along Y-axis
= velocity of migrating robin relative to air = 12 j m/s
(where "j" is unit vector in Y-direction)
= velocity of air relative to ground = 6.3 i m/s
(where "i" is unit vector in X-direction)
= velocity of migrating robin relative to ground = ?
using the equation
=
+
= 12 j + 6.3 i
= 6.3 i + 12 j
magnitude : sqrt((6.3)² + (12)²) = 13.6 m/s
direction : tan⁻¹(12/6.3) = 62.3 deg north of east
Answer:
304.86 metres
Explanation:
The x and y cordinates are and
respectively
The horizontal distance travelled,
Making t the subject,
Since , we substitute t with the above and obtain
Making d the subject we obtain
d=304.8584
d=304.86m