The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies
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Answer:
a) the pattern is bright, b) y = 8.25 mm, c) the distance increases with the wavelength increases
Explanation:
This is a team building exercise to perform interference experiments, where the separation of the slits is d = 1 m = 1 10⁻³ m and the distance to the screen L = 1.5 m
Constructive interference occurs when the path difference is equal to an integer number of wavelengths
d sin θ = m λ
a) The center of the two-ray pattern has the same length so the intensity is MAXIMUM, that is, the pattern is bright
b) to find the distance let's use trigonometry
tan θ= y / L
tan θ =sin θ/cos θ= sin θ
because the angles are small
we substitute
y =
let's calculate
y = 10 550 10⁻⁹ 1.5 / 1 10⁻³
y = 8.25 10⁻³ m
c) for this part the incident light must be white or polychrome light
let's find the distance (y) for some colors, in the first order
Violet λ = 400
y = 1 400 10⁻⁹ 1.5 / 1 10⁻³
y = 6 10⁻⁴ m
green λ = 500 nm
y = 1 500 10⁻⁹ 1.5 / 1 10⁻³
y = 7.5 10⁻⁴ m
yellow λ = 600 nm
y = 1 600 10⁻⁹ 1.5 / 1.10⁻³
y = 9 10⁻⁴ m
lam λ = 700 nm
y = 1 700 10⁻⁹ 1.5 / 1. 10⁻³
y = 1.05 10⁻³ m
violet, green, orange, red
the distance increases with the wavelength increases
d) To find the wavelength we must measure the distance y from the center of the slit for various interference orders and using the equation we can find the wavelength of rationality
Answer:
The increase in potential energy of the ball is 115.82 J
Explanation:
Conceptual analysis
Potential Energy (U) is the energy of a body located at a certain height (h) above the ground and is calculated as follows:
U = m × g × h
U: Potential Energy in Joules (J)
m: mass in kg
g: acceleration due to gravity in m/s²
h: height in m
Equivalences
1 kg = 1000 g
1 ft = 0.3048 m
1 N = 1 (kg×m)/s²
1 J = N × m
Known data
Problem development
ΔU: Potential energy change
ΔU = U₂ - U₁
U₂ - U₁ = mₓgₓh₂ - mₓgₓh₁
U₂ - U₁ = mₓg(h₂ - h₁)
The increase in potential energy of the ball is 115.82 J
Answer: a) speed = 3.45 × 10^-2 m/s
b) speed = 1.38 × 10^-1 m/s
Explanation: shown in the attachment
