Explanation:
Given that,
Frequency of train horn, f = 218 Hz
Speed of train,
The speed of sound, V = 344 m/s (say)
The speed of the observed person,
(a) When the train approaches you, the Doppler's effect gives the frequency as follows :
(b) When the train moves away from you, the Doppler's effect gives the frequency as follows :
Hence, this is the required solution.
Answer:
Explanation:
The acceleration of the car is given by:
where
v is the final velocity
u is the initial velocity
t is the time
Here we have to convert the velocities from mi/hr to m/s. Keeping in mind that
1 mi = 1609 m
1 h = 3600 s
We get:
While the time interval is
t = 4.0 s
Substituting,
Answer:
6.9066 × 10⁻⁵ m
Explanation:
For constructive interference, the expression is:
Where, m = 1, 2, .....
d is the distance between the slits.
The formula can be written as:
....1
The location of the bright fringe is determined by :
Where, L is the distance between the slit and the screen.
For small angle ,
So,
Formula becomes:
Using 1, we get:
Thus, the distance between the central maximum is 3.00 cm
First bright fringe , m = 1 occur at 3.00 / 2 = 1.50 cm
Since,
1 cm = 0.01 m
y = 0.0150 m
Given L = 2.00 m
λ = 518 nm
Since, 1 nm = 10⁻⁹ m
So,
λ = 518 × 10⁻⁹ m
Applying the formula as:
<u>⇒ d, distance between the slits = 6.9066 × 10⁻⁵ m</u>