Shale, and Sandstone are the rocks formed by precipitation of calcium carbonate from sea water.
Option B and D
<u>Explanation:</u>
Calcium carbonate can get precipitated from sea water and it forms rocks termed as limestones. These limestones are a variety of sedimentary rocks. Along with it, shale and sandstones are also varieties of sedimentary rocks and they also contain some of the precipitation of calcium carbonate.
The composition of sandstones consists of quartz and feldspar along with some of the composition of calcium carbonate. The same concept goes for Shale also. Basically, Shale is a mixuture of Clay but they can combine with limestone.
Thus, Shale, Sandstone and limestones are the rocks formed by precipitation of calcium carbonate from sea water.
Answer:
Explanation:
NaCl = Na⁺ + Cl⁻
6120 ions of NaCl will contain 3060 ions of Na⁺ and 3060 ions of Cl⁻ , forming 3060 molecules of NaCl .
6.02 x 10²³ molecules of NaCl = 1 mole
3060 molecules of NaCl = 3060 x 10⁻²³ / 6.02 moles
= 508.30 x 10⁻²³ moles
= 5.08 x 10⁻²¹ moles
Answer : 5.08E-21 moles .
Answer:
The geologist time scale was formed when scientists studied rock layers and index fossils worldwide. With this information, they placed Earth's rocks in order by relative age. Later, radioactive dating helped determine the exact age of the divisons in the geologic time scale.
This scale is organized by the 4.6 billion years of earth's history into sections based on important changes seen in the geologic record. The largest intervals are called eons, with each eon containing many millions of years.
In precambarian time the processes that affect Earth's surface have lessened the erosion on the surface. Earth was being hit by meteorites every second. Now there is water erosion and there wasn't back then. The surface changes have lessened over time.
I think the answer is C but don’t quote me on that
Answer:
237.2 mL.
Explanation:
- We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.
(XMV) acid = (XMV) base.
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
<em>(XMV) HCl = (XMV) NaOH.</em>
<em></em>
For HCl; X = 1, M = 0.5 M, V = ??? mL.
For NaOH, X = 1, M = 1.54 M, V = 77.0 mL.
<em>∴ V of HCl = (XMV) NaOH / (XV) HCl = (</em>1)(1.54 M)(77.0 mL) / (1)(0.5 M) = <em>237.2 mL.</em>
