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PtichkaEL [24]
3 years ago
5

The Atlantic Ocean is expanding. What does this tell us about plates under the Atlantic Ocean?

Chemistry
2 answers:
FromTheMoon [43]3 years ago
7 0
B. They are being forced apart.
KiRa [710]3 years ago
4 0
The answer is B, they are being forced apart.
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How many molecules in 2.00 mol of sucrose, C12H22O11??
svetlana [45]
2.00 mol C12H22O11 x (6.02 x 10^23 molecule C12H22O11 / 1 mol C12H22O11) = 1.20 x 10^24 molecules C12H22O11 
hopes this answer helps :) :D :) 
4 0
3 years ago
How many moles of br2(l) (mm = 159.80 g/mol) are in 13.9 ml of liquid bromine? the density of br2(l) is 3.12 g/ml?
diamong [38]

Answer:

             Moles  =  0.271 mol

Solution:

Step 1: Calculate Mass of Br₂ as;

                               Density  =  Mass  ÷  Volume

Solving for Mass,

                               Mass  =  Density  ×  Volume

Putting values,

                               Mass  =  3.12 g.mL⁻¹  ×  13.9 mL

                               Mass  =  43.36 g

Step 2: Calculate Moles of Br₂ as;

                               Moles  =  Mass  ÷  M.Mass

Putting values,

                               Moles  =  43.36 g ÷  159.80 g.mol⁻¹

                              Moles  =  0.271 mol

7 0
3 years ago
What happens when you mix calcium chloride and hydrogen peroxide?
Natalka [10]

Answer:

Explanation: When chlorine reacts with hydrogen peroxide, hydrogen peroxide falls apart into water and oxygen. Chlorine gas hydrolyses into hypochlorous acid (, which subsequently  into hypochlorite ions . The reaction between hydrogen peroxide and hypochlorite takes place very quickly.

8 0
3 years ago
Procaine hydrochloride ( MW = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which ha
fenix001 [56]

Answer:

\boxed{\text{2.274 mol/L}}

Explanation:

b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}

Assume 1 kg water.

1. Moles of P.HCl

Then we have 4.666 mol of P.HCl

2. Mass of P.HCl

n = 4.666 mol × 272.77 g/mol = 1271.1 g

3. Total mass of solution

m = 1000 g + 1271.1 g = 2271.1 g solution

4. Volume of solution

V = \text{2271.1 g} \times \dfrac{\text{1 mL}}{\text{1.1066 g}} = \text{2052.3 mL} = \text{2.0523 L}

5. Molar concentration  

\begin{array}{rcl}c & = & \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c & = & \dfrac{\text{4.666 mol}}{\text{2.0523 L}}\\\\ & = & \text{2.274 mol/L}\\\end{array}\\

\text{The molar concentration of the solution is} \boxed{\textbf{2.274 mol/L}}

5 0
4 years ago
PLEASE HELP!!!!!!!!!
KonstantinChe [14]

Answer:

Option "C" is the correct answer to the following question.

Explanation:

Given:

Pressure in an automobile tire (P) = 1.88 atm

Temperature (K) = 25°C = 273 + 25 = 298 Kelvin

New temperature (K1) = 37°C = 273 + 37 = 310 Kelvin

Find:

New pressure in an automobile tire (P1) = ?

Computation:

\frac{P}{K}= \frac{P1}{K1} \\\\\frac{1.88}{298}= \frac{P1}{310}\\\\1.9557

New pressure in an automobile tire (P1) = 1.9557

New pressure in an automobile tire (P1) = 1.96 (Approx)

5 0
3 years ago
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