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likoan [24]
3 years ago
14

A major-league pitcher can throw a baseball in excess of 44.7 m/s. If a ball is thrown horizontally at this speed, how much will

it drop by the time it reaches the catcher who is 16.1 m away from the point of release?
Physics
1 answer:
Sloan [31]3 years ago
6 0
<h2>The baseball drops by 0.64 meter.</h2>

Explanation:

Consider the horizontal motion of ball

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 44.7 m/s

        Acceleration, a = 0 m/s²  

        Displacement, s = 16.1 m      

     Substituting

                      s = ut + 0.5 at²

                      16.1 = 44.7 x t + 0.5 x 0 x t²

                      t = 0.36 s

      Time taken to travel 16.1 m is 0.36  seconds

Now we need to find how much ball travel vertically during this 0.36 seconds.

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = 9.81 m/s²  

        Time, t = 0.36 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 0 x 0.36 + 0.5 x 9.81 x 0.36²

                      s = 0.64 m

     The baseball drops by 0.64 meter.

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Answer:

<em>D. refraction</em>

Explanation:

Refraction: Refraction is change in direction of light rays. Refraction occurs whenever light rays travels from a transparent medium to another transparent medium of different density. The abrupt change in direction at the surface of the surface of the two media is referred to as <em>refraction</em><em>.</em>

<em>Refraction occurs when light travels from air to glass or from air to liquid.</em>

<em>Laws Of Refraction:</em>

(i) The incident ray, the refracted ray and the normal, all at the point of incident lies in the same plane.

(ii) The ratio of the sine of the angle of incident to the sine of the angle of refraction is a constant for a given pair of media.

<em>Thus the right option is D. refraction</em>

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A ray is incident on a film of thickness t and the index of refraction n=1.6 at an angle θ = 35 degrees. Find the angle of refra
lidiya [134]

Answer

Given,

refractive index of film, n = 1.6

refractive index of air, n' = 1

angle of incidence, i = 35°

angle of refraction, r = ?

Using Snell's law

n' sin i = n sin r

1 x sin 35° = 1.6 x sin  r

 r = 21°

Angle of refraction is equal to 21°.

Now,

distance at which refractive angle comes out

d = 2.5 mm

α be the angle with horizontal surface and incident ray.

α = 90°-21° = 69°

t be the thickness of the film.

So,

tan \alpha = \dfrac{t}{d/2}

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t = 2.26 mm

Hence, the thickness of the film is equal to 2.26 mm.

4 0
3 years ago
Three identical resistors have an equivalent resistance 15.6 ohm when they are connected in series. What is the resistance for e
attashe74 [19]

Answer:

R=5.2\ \Omega

Explanation:

In series combination, the equivalent resistance is given by :

R_{eq}=R_1+R_2+R_3+...

Let the identical resistors be R. We have, R_{eq}=15.6\ \Omega

So,

R+R+R=15.6\\\\3R=15.6\\\\R=\dfrac{15.6}{3}\\\\R=5.2\ \Omega

So, the resistance of each resistor is 5.2\ \Omega.

4 0
3 years ago
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