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USPshnik [31]
3 years ago
5

An astronaut whose mass is 80. kg and is initially at rest carries an empty oxygen tank with a mass of 10. kg. He throws the tan

k away from himself with a speed of 2.0 m/s. With what velocity does he start to move off into spa
Physics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

0.25 m/s

Explanation:

From the law of conservation of momentum

Mu+ mu = Mv' + m v

M= mass of the astronaut = 80 kg

m= mass of the oxygen tank= 10 Kg

v= speedof the tank 2 m/s

u= initial velocity of the system= 0

If we substitute the values, we have

( 80× 0 )+(10×0)= [(80 x v )+ (10 x 2)]

0= 80v + 20

-20=80v

v= -0.25 m/s ( we have a negative value because the astronaut and the motion of the cylinder are in opposite direction)

Hence the velocity the astronaut start to move off into space is 0.25 m/s

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Please help me solve all of them ( a, b, c and d ) thankiew !! <br> I’m also kind of in a rush
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Answer:

a-

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9V = I ×( 12+6)

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c

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d

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2 years ago
What is the magnification of a virtual image if the image is 60.0 cm from a
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6 0
3 years ago
Read 2 more answers
Denial cycled at 6 mph for 0.8 h. Then he jogged at 2 mph for
dexar [7]
<h3>Deniel's average speed for the total</h3><h3>distance is 3.6 mph</h3>

Average speed is difined as the total distance travelled divided by the total time required to cover the distance. Mathematically, it is expressed as:

Ave. Speed = \frac{Total distance }{Total time}

To obtain the average speed of Daniel, we shall determine the distance travelled in each case. This is illustrated below:

<h3>Case 1:</h3>

Speed 1 (S₁) = 6 mph

Time 1 (t₁) = 0.8 h.

<h3>Distance 1 (D₁) =? </h3>

Speed = \frac{Distance}{Time} \\\\S_{1}  = \frac{D_{1}}{t_{1}} \\\\6 = \frac{D_{1}}{0.8}

Cross multiply

D₁ = 6 × 0.8

<h3>D₁ = 4.8 mile</h3>

<h3>Case 2:</h3>

Speed 2 (S₂) = 2 mph

Time 2 (t₂) = 1.2 h.

<h3>Distance 2 (D₂) =? </h3>

S_{2} = \frac{D_{2}}{t_{2}}\\\\2 = \frac{D_{2}}{1.2}

Cross multiply

D₂ = 2 × 1.2

<h3>D₂ = 2.4 mile </h3>

Next, we shall determine the total time. This can be obtained as follow:

Time 1 (t₁) = 0.8 h.

Time 2 (t₂) = 1.2 h.

<h3>Total time (T) =? </h3>

T = t₁ + t₂

T = 0.8 + 1.2

<h3>T = 2 h</h3>

Next, we shall determine the total distance. This can be obtained as follow:

Distance 1 (D₁) = 4.8 mile

Distance 2 (D₂) = 2.4 mile

<h3>Total distance (D) =?</h3>

D = D₁ + D₂

D = 4.8 + 2.4

<h3>D = 7.2 mile</h3>

Finally, we shall determine the average speed of Daniel. This can be obtained as follow:

Total time = 2 h

Total distance  = 7.2 mile

<h3>Average speed =?</h3>

Ave. speed = \frac{Total distance }{Total time} \\\\Ave. speed = \frac{7.2 }{2}

<h3>Average speed = 3.6 mph</h3><h3 />

Therefore, the average speed of Daniel is 3.6 mph

Learn more: brainly.com/question/680492

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