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USPshnik [31]
3 years ago
5

An astronaut whose mass is 80. kg and is initially at rest carries an empty oxygen tank with a mass of 10. kg. He throws the tan

k away from himself with a speed of 2.0 m/s. With what velocity does he start to move off into spa
Physics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

0.25 m/s

Explanation:

From the law of conservation of momentum

Mu+ mu = Mv' + m v

M= mass of the astronaut = 80 kg

m= mass of the oxygen tank= 10 Kg

v= speedof the tank 2 m/s

u= initial velocity of the system= 0

If we substitute the values, we have

( 80× 0 )+(10×0)= [(80 x v )+ (10 x 2)]

0= 80v + 20

-20=80v

v= -0.25 m/s ( we have a negative value because the astronaut and the motion of the cylinder are in opposite direction)

Hence the velocity the astronaut start to move off into space is 0.25 m/s

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Answer:

C) >A)>B)

Explanation:

We know that force per unit area is known as pressure.But we have to understand that this force should be perpendicular to the area.

 P = F/A

P=Pressure

F= Force

A=Area

A)

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F= ΔP x A

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B)

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F= 4230 N

C)

Given that

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5 0
3 years ago
At a certain instant the current flowing through a 5.0-H inductor is 3.0 A. If the energy in the inductor at this instant is inc
lys-0071 [83]

Answer:

The current is changing at the rate of 0.20 A/s

Explanation:

Given;

inductance of the inductor, L = 5.0-H

current in the inductor, I = 3.0 A

Energy stored in the inductor at the given instant, E = 3.0 J/s

The energy stored in inductor is given as;

E = ¹/₂LI²

E = ¹/₂(5)(3)²

E = 22.5 J/s

This energy is increased by 3.0 J/s

E = 22.5 J/s + 3.0 J/s = 25.5 J/s

Determine the new current at this given energy;

25.5 = ¹/₂LI²

25.5 = ¹/₂(5)(I²)

25.5 = 2.5I²

I² = 25.5 / 2.5

I² = 10.2

I = √10.2

I = 3.194 A/s

The rate at which the current is changing is the difference between the final current and the initial current in the inductor.

= 3.194 A/s - 3.0 A/s

= 0.194 A/s

≅0.20 A/s

Therefore, the current is changing at the rate of 0.20 A/s.

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