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Charra [1.4K]
3 years ago
6

A car has positive acceleration. What information can you infer from this? A- The car is changing direction. B- The car is speed

ing up in the same direction as it is traveling. C- The car is slowing down and changing the direction it is traveling. D- The car is slowing down.
Physics
2 answers:
Semmy [17]3 years ago
6 0

Answer:

Assuming rightward is positive, the velocity is positive whenever the car is moving to the right, and the velocity is negative whenever the car is moving to the left. The acceleration points in the same direction as the velocity if the car is speeding up, and in the opposite direction if the car is slowing down.

kvv77 [185]3 years ago
5 0

Answer:

answe is b

Explanation:

A positive acceleration is defined as change of velocity upwards the direction that the object has taken. Therefore, a car having a positive acceleration means that the car is speeding up in the same direction as it traveling.

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Where and when does the sun stay up for 24hours
DIA [1.3K]

Answer:

abisko, sweden

Explanation:

A bisco is the home to their eyes sky station an epic center for Aurora expanses and northern Sweden. During summer months, the Sun Bates to town and up to 24 hours of sunlight per day.

5 0
3 years ago
A car starts from rest and drives at 45 m/s in 20 s. how far did it travel
Schach [20]

Answer:

distance=speed×time.

45×20=900m.

6 0
3 years ago
A stretched string has a mass per unit length of 5.40 g/cm and a tension of 17.5 N. A sinusoidal wave on this string has an ampl
kondaur [170]

Answer:

Part a)

y_m = 0.157 mm

part b)

k = 101.8 rad/m

Part c)

\omega = 579.3 rad/s

Part d)

here since wave is moving in negative direction so the sign of \omega must be positive

Explanation:

As we know that the speed of wave in string is given by

v = \sqrt{\frac{T}{m/L}}

so we have

T = 17.5 N

m/L = 5.4 g/cm = 0.54 kg/m

now we have

v = \sqrt{\frac{17.5}{0.54}}

v = 5.69 m/s

now we have

Part a)

y_m = amplitude of wave

y_m = 0.157 mm

part b)

k = \frac{\omega}{v}

here we know that

\omega = 2\pi f

\omega = 2\pi(92.2) = 579.3 rad/s

so we  have

k = \frac{579.3}{5.69}

k = 101.8 rad/m

Part c)

\omega = 579.3 rad/s

Part d)

here since wave is moving in negative direction so the sign of \omega must be positive

4 0
3 years ago
A sound wave travels in air toward the surface of a freshwater lake and enters into the water. The frequency of the sound does n
Shkiper50 [21]

Answer:

Explanation:

velocity of sound in air at 20⁰C is 343 m /s

velocity of sound in water at 20⁰C is 1481 m /s

The wavelength of the sound is 2.86 m in the air so its frequency

= 343 / 2.86 = 119.93 .

This frequency of  119.93 will remain unchanged in water .

wavelength in water = velocity in water / frequency

= 1481 / 119.93

= 12. 35 m .

7 0
3 years ago
If the force of a golf club on a golf ball is 200 N forward, what will the force of the ball on the club be? A. 200 N forward B.
Korolek [52]

The ball should put 200 N of force towards the golfer.

Newton's Third Law is every action has an equal and opposite reaction.

It's the ball exerting 200 N of force towards the club as well, but the opposite reaction is that it flies away.

8 0
3 years ago
Read 2 more answers
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