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r-ruslan [8.4K]
2 years ago
7

Semiconductors are more effective than metals as converters of solar radiation into electricity because?

Chemistry
1 answer:
DedPeter [7]2 years ago
6 0

Semiconductors show the property of both the conductor and insulator. They are more effective than metals as their valence electron can free flow by the sun's energy. Thus, option B is correct.

<h3>What are semiconductors?</h3>

Semiconductors are substances and materials that exhibit intermediate properties of conductors and insulators. They are solid materials that can conduct electrical charges due to the added impurity or change in temperature.

They have a valence electron in their outer shell that can absorb the energy from the sun to get excited. This leads to the flow of the charge in the semiconducting substance more easily.

Therefore, option B. the semiconductors can absorb the extra energy is correct.

Learn more about semiconductors here:

brainly.com/question/18132856

#SPJ4

Your question is incomplete, but most probably your full question was, Semiconductors are more effective than metals as converters of solar radiation into electricity because

A. it is easier for the atoms of a semiconductor to absorb solar energy and to move from place to place within the solid, thereby conducting electricity.

B. the energy contained in sunlight gives the valence electrons in the semiconductor atoms the extra energy they need to "flow" throughout the solid.

C. metals melt much too easily under direct sunlight and, as liquids, lose their ability to conduct electricity.

D. solar radiation has sufficient energy to knock electrons completely off the metal surface, making it impossible for the electrons to "flow" from atom to atom and conduct electricity.

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1-<span>Largest planet in the solar system
2-</span><span>Has no moons
3- True
4-</span><span>They orbit the sun
5- Earth
6-</span><span>They orbit the sun.</span>
3 0
4 years ago
Read 2 more answers
Find the molar mass of PCI3
Pavlova-9 [17]

Answer: around 137.33

Explanation:

4 0
3 years ago
The prefix 'kilo-' means a thousand. So a kilo-gram is a thousand grams. 1 kilogram=1,000 grams How many kilograms is 1,008 gram
lesantik [10]

<u>Answer:</u>  1.0 kilograms.

<u>Explanation:</u>

One kilogram is equal to a thousand grams.

Supposing x to be the number of kilograms equal to one thousand and eight grams, we can write it as:

1 kg = 1000 grams

x kg = 1008 grams

To solve for x, we can simply divide 1008 grams by 1000 thousand grams to get the answer.

x = 1008 / 1000

x = 1.008

Rounding this value to the nearest tenth, it will become 1.0 kilograms.

4 0
4 years ago
An Argon atom will do which of the following when it forms an ion? Choose all that apply and are correct.
sattari [20]

Answer:

A

Explanation:

Noble gases are already stable

And since Argon is a noble gas it is stable

5 0
3 years ago
A certain liquid X has a normal freezing point of 7.60 °C and a freezing point depression constant K= 6.90 °C-kg-mol. Calculate
Dmitry [639]

<u>Answer:</u> The freezing point of solution is -5.11°C

<u>Explanation:</u>

Vant hoff factor for ionic solute is the number of ions that are present in a solution. The equation for the ionization of sodium chloride follows:

NaCl(aq.)\rightarrow Na^{+}(aq.)+Cl^-(aq.)

The total number of ions present in the solution are 2.

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (NaCl) = 7.57 g

M_{solute} = Molar mass of solute (NaCl) = 58.44 g/mol

W_{solvent} = Mass of solvent (liquid X) = 350.0 g

Putting values in above equation, we get:

\text{Molality of }NaCl=\frac{7.57\times 1000}{58.44\times 350.0}\\\\\text{Molality of }NaCl=0.370m

To calculate the depression in freezing point, we use the equation:

\Delta T=iK_fm

where,

i = Vant hoff factor = 2

K_f = molal freezing point depression constant = 6.90°C/m

m = molality of solution = 0.370 m

Putting values in above equation, we get:

\Delta T=2\times 6.90^oC/m.g\times 0.370m\\\\\Delta T=5.11^oC

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T=\text{freezing point of water}-\text{freezing point of solution}

\Delta T = 5.11 °C

Freezing point of water = 0°C

Freezing point of solution = ?

Putting values in above equation, we get:

5.106^oC=0^oC-\text{Freezing point of solution}\\\\\text{Freezing point of solution}=-5.11^oC

Hence, the freezing point of solution is -5.11°C

7 0
4 years ago
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