1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NISA [10]
2 years ago
11

Join my me et.gogle .etj-dovn-kds​

Physics
1 answer:
s2008m [1.1K]2 years ago
8 0

Answer:

ok

but I would like to think this is not a scam

You might be interested in
Light-rail passenger trains that provide transportation within and between cities are capable of modest accelerations. The magni
Mkey [24]
During the first phase of acceleration we have:
v o = 4 m/s;  t = 8 s; v = 13 m/s, a = ?
v = v o + a * t
13 m/s = 4 m / s + a * 8 s
a * 8 s = 9 m/s
a = 9 m/s : 8 s
a = 1.125 m/s²
The final speed:
v = ?;  v o = 13 m/s; a = 1.125 m/s² ;  t = 16 s
v = v o + a * t
v = 13 m/s + 1.125 m/s² * 16 s
v = 13 m/s + 18 m/s = 31 m/s 
3 0
3 years ago
Considerando que você comece a caminhar em velocidade constante, inicialmente a 350 m de um ponto referencial escolhido. Você ca
ExtremeBDS [4]

Answer:

a. S(t)=350−1t

Explanation:

To determine the equation of motion you take into account the general form of motion with constant velocity:

S(t)=S_o+vt    ( 1 )

So is the initial position from a specific reference frame. In this case is 350 m.

v is the speed of the motion, in this case is 1m/s. However, the motion is forward the zero point of the reference frame, hence, the speed is - 1m/s.

You replace the values of So and v in the equation ( 1 ) and you obtain:

S(t)=350-(1m/s)t

Hence, the answer is:

a. S(t)=350−1t

- - - - - - - - - - - - - - - - - - - - -

Para determinar a equação do movimento, você leva em consideração a forma geral do movimento com velocidade constante:

             (1)

Assim é a posição inicial de um quadro de referência específico. Neste caso, é de 350 m.

v é a velocidade do movimento, neste caso é de 1m / s. No entanto, o movimento é avançar o ponto zero do quadro de referência, portanto, a velocidade é de - 1m / s.

Você substitui os valores de So ev na equação (1) e obtém:

Portanto, a resposta é:

uma. S (t) = 350-1t, movimento retrógrado

4 0
3 years ago
Pls help i will be so happy thank you
Anvisha [2.4K]

Answer:

below given.

Explanation:

1) linear/direct

2) Indirect

3) linear/direct

4)  quadratic

5) Inverse

6) linear/direct

7) Inverse / Indirect

8) Inverse / Indirect

4 0
3 years ago
Gravity on earth is 9.8 m/s squared, and gravity on the moon is 1.6 m/s squared. So if the mass of an object on earth is 40 kilo
garik1379 [7]

The mass of an object on Earth is the same as its mass on the Moon. The weight is different.

Weight = m * g

Weight ( Moon ) = 40 kg * 1.6 m/s² = 64 N

If the mass of an object on Earth is 40 kg, its mass on the Moon is 40 kg and its weight on the Moon is 64 N. 

7 0
3 years ago
I NEED HELP ASAP!!!
alekssr [168]

Answer:

B) 3.6x 10_6 N/C or D)2.8 x105 N/C

7 0
3 years ago
Other questions:
  • Describe what it means to view something from a frame of reference. Give an example to illustrate your explanation.
    10·1 answer
  • The process by which atoms are arranged to form a material with a crystal shape is called
    9·2 answers
  • Which of the following are characteristics of heterogeneous mixtures?
    15·1 answer
  • Some steamboat restaurants use paper pots for their customers to boil the food themselves. What is the reason for the paper not
    13·1 answer
  • soaring birds and glider pilots can remain aloft for hours without expending power. Discuss why this is so.
    12·1 answer
  • An example of kinetic energy is ______.
    11·2 answers
  • Liquid pressure does not depend on
    6·1 answer
  • What is the equivalent resistance of the circuit?
    9·1 answer
  • Help me pls I WILL GIVE BRAINIEST I DONT CARE PLS HELP
    6·2 answers
  • George is pushing a box horizontally on the floor. The box has a mass of 10 kg and as a
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!