Answer:
When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.
Image result for I need help find how much tension is in the string???? And can you explain how you got it after you get the answer plz????
Hence, in such a case the tension will be equal to the centrifugal force.
Formula for tension = centrifugal force = mv2/r.
So the formula of tension will be = centripetal force – force of gravity = mv2/r – mg = m(v2/r-g)
The formula of tension will be = centripetal force + force of gravity = mv2/r + mg = m(v2/r+g)
Explanation:
Answer:
<h2>B. 20°</h2>
Explanation:
Range in projectile is defined as the distance covered in the horizontal direction. It is expressed as R = U²sin2Ф/g
U is the initial velocity of the body (in m/s)
Ф is the angle of projection
g is the acceleration due to gravity.
Given U = 14m/s, g = 9.8m/s and range R = 15 m
we will substitute this value into the formula to get the projection angle Ф as shown;
15 = 15²sin2Ф/9.8
15*9.8 = 15²sin2Ф
147 = 225sin2Ф
sin2Ф = 147/225
sin2Ф = 0.6533
2Ф = sin⁻¹0.6533
2Ф = 40.79°
Ф = 40.79°/2
Ф = 20.39° ≈ 20°
Hence, the range is greatest at angle 20°
Answer:
Which of the following... : constant velocity horizontal motion
A ball is thrown at certain... : 0 m/s
Pretty fast. Everything looks fast when running past a light pole
Answer:
12 km/h
Explanation:
Average Speed = Distance / Time (or rate)
Pick a point on the graph for Ian and plug in values.
For example, 20 minutes -> 4km
Hence, Average speed = 4km ÷ 20 minutes = 0.2 km/min
0.2 km/min × 60 = 12 km/h
