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3 years ago

When the distance between two masses is doubled, the gravitational attraction between

Physics

1 answer:

mrs_skeptik [129]3 years ago

5 0

The new gravitational attraction will be 1/4 as much

Explanation:

The magnitude of the gravitational force between two objects is given by

$F=G\frac{m_1 m_2}{r^2}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}$ is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, the original force between the two objects is F, when they are separated by a distance r.

Later, the distance between the two objects is doubled, so the new distance is

$r'=2r$

Therefore, the new force will be

$F'=G\frac{m_1 m_2}{(2r)^2}=\frac{1}{4}(\frac{Gm_1 m_2}{r^2})=\frac{F}{4}$

Therefore, the new force will be one-fourth as much.

Learn more about gravitational force:

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A well-insulated cup of water is too hot to make tea, so you mixed it with an equal amount of cool water to lower the temperatur

KonstantinChe [14]

Answer:The change in entropy of the total amount of water is negative as a result of the mixing.

Explanation:If you increase temperature, you increase entropy

Also More energy gives you greater entropy and randomness of the atoms.

4 0

3 years ago

(a) What is the current involved when a truck battery sets in motion 720 C of charge in 4.00 s while starting an engine? (b) How

OLEGan [10]

Answer:

(a) Current flowing through truck battery is 180 A

(b) Time taken in calculator is 333.33 s

Explanation:

(a) Given:

The charge on the truck battery,q = 720 C

Time, t = 4.00 s

Consider I be the current flowing through truck battery.

The relation between current, charge and time is:

I = q/t

Substitute the suitable values in the above equation.

$I=\frac{720}{4}$

I = 180 A

(b) Given:

The charge on the calculator,q = 7.00 C

The current flowing through calculator, I = 0.3 mA = 0.3 x 10⁻³ A

Consider t be the time.

The relation between current, charge and time is:

t = q/I

Substitute the suitable values in the above equation.

$t=\frac{1}{0.3\times10^{-3} }$

I = 333.33 s

8 0

4 years ago

Please help !!

ExtremeBDS [4]

Answer:

Just as the angles of the sun, moon and Earth affect tidal heights over the course of a lunar month, so do their distances to one another. Because the moon follows an elliptical path around the Earth, the distance between them varies by about 31,000 miles over the course of a month.

Hope this helped, have a nice rest of your day!

3 0

3 years ago

An electrolyte is . . . . .

Rus_ich [418]

Answer:

b) a compound which produces ions dissolved in a solution that conduct electricity.

NaCl is an electrolyte.

7 0

2 years ago

Your cat Goldie (mass 8.50 kg ) is trying to make it to the top of a frictionless ramp 39.930 m long and inclined 27.0 ∘ above t

Citrus2011 [14]

Answer:

The speed when se reaches the top of the incline is 0.28 m/s

Explanation:

The work done is equal to the change of kinetic energy, then:

Wg + Wf + Wn = ΔEk

Where

Wg = work done by gravity

Wf = work done by force

Wn = work done by normal force

$-mgdsin\theta +Fd+0=\frac{1}{2} *m*(v_{2} ^{2} -v_{f} )$

Where

m = 8.5 kg

g = 9.8 m/s²

d = 39.93 m

F = 37.4 N

vf = 2 m/s

Replacing:

$39.93*(-8.5*9.8*sin27+34.4)=\frac{1}{2} *8.5*(v_{2} ^{2} -2^{2} )\\v_{2} =0.28m/s$

7 0

4 years ago