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yarga [219]
3 years ago
10

When the distance between two masses is doubled, the gravitational attraction between

Physics
1 answer:
mrs_skeptik [129]3 years ago
5 0

The new gravitational attraction will be 1/4 as much

Explanation:

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, the original force between the two objects is F, when they are separated by a distance r.

Later, the distance between the two objects is doubled, so the new distance is

r'=2r

Therefore, the new force will be

F'=G\frac{m_1 m_2}{(2r)^2}=\frac{1}{4}(\frac{Gm_1 m_2}{r^2})=\frac{F}{4}

Therefore, the new force will be one-fourth as much.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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Answer:

The answer is "Location Y"

Explanation:

Please find the complete question in the attachment.

As we show in the graph when the marble rolling with the full force it will stop on the y location because it is curved, and the marble can't move to another location, that's why the maximum kinetic energy of the marble is at the y location.

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3 years ago
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the answer would be D

hope this helps!

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4 years ago
You are making cookies that call for 3 tablespoons of molasses, but you are having trouble measuring out the thick, syrupy liqui
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4 years ago
Read 2 more answers
Please help me with this question
valkas [14]

Answer: m∠P ≈ 46,42°

because using the law of sines in ΔPQR

=> sin 75°/ 4 = sin P/3

so ur friend is wrong due to confusion between edges

+) we have: sin 75°/4 = sin P/3

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