Near the Earth's surface, a freely falling body has constant acceleration at every instant of its fall ... 9.8 meters per second^2.
Vf = vi + at
vf = 6 + (2)(12)
vf = 6 + 24
vf = 30
2as = vf² - vi²
2(2)s = (30)² - (6)²
4s = 900 - 36
4s = 864
s = 864/4
s = 216
<span>d = 216</span>
It is in equilibrium if its velocity is not changing.
Answer:
The smallest value is n= 2
Explanation:
The balmer equation is given below
1/λ = R(1/4 - 1/n₂²).
R= 1.0973731568508 × 10^7 m^-1
λ= 400*10^-9 m
(400*10^-9)= 1.0973731568508 × 10^7 (1/4-1/n²)
(400*10^-9)/1.0973731568508 × 10^7
= 1/4 - 1/n²
364.51 *10^-16= 1/4 - 1/n²
1/n²= 1/4 -364.51 *10^-16
1/n² = 0.25-3.6451*10^-14
1/0.25= n²
4= n²
√4= n
2= n
The smallest value is N= 2
