1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Artyom0805 [142]
3 years ago
5

Which of the following gives the definition of ion-dipole attraction? Select the correct answer below: O a. lon-dipole attractio

n is attraction between an ion and the polar bond(s) in a nonpolar mo b. lon-dipole attraction is a physical process accompanying the dissolution of an ionic compound in which the compound's constituent ions are solvated and dispersed throughout the solution. c. lon-dipole attraction is the scattering of visible light by a solution. d. lon-dipole attraction is the electrostatic attraction between an ion and a polar molecule.
Chemistry
1 answer:
frez [133]3 years ago
6 0

Answer:

D

Explanation:

Anions are attracted to the positive end of a dipole, while the cations are attracted to the negative end. As the size of the dipole moment or the ionic charge increases, the vastness of the attraction also increases. This type of attraction is important for solutions of ionic substances in polar liquids.

You might be interested in
Explain why Nitrogen -17 is unstable
Yuri [45]
Has only 7 electrons so it want to bond with other elements so its very reactive and unstable. Hope this helps
4 0
1 year ago
From his experiment j.j. Thomson concluded that
iragen [17]
Particles as small as atoms exist.
3 0
3 years ago
Assume that silver and gold form ideal, random mixtures. Calculate the mass of pure Ag needed to cause an entropy increase of 20
KengaRu [80]

Answer:

m_{Ag}=2,265.9g

Explanation:

Hello!

In this case, since the definition of entropy in a random mixture is:

\Delta S=-n_TR\Sigma[x_i*ln(x_i)]

For this silver-gold mixture we write:

\Delta S=-(n_{Au}+n_{Ag})R\Sigma[\frac{n_{Au}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Au}}{n_{Au}+n_{Ag}} )+\frac{n_{Ag}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Ag}}{n_{Au}+n_{Ag}} )]

By knowing the moles of gold:

n_{Au}=100g*\frac{1mol}{197g} =0.508mol

It is possible to write the aforementioned formula in terms of the variable x representing the moles of silver:

20\frac{J}{mol}=-(0.508+x)8.314\frac{J}{mol*K} \Sigma[\frac{0.508}{0.508+x} *ln(\frac{0.508}{0.508+x} )+\frac{x}{0.508+x} *ln(\frac{x}{0.508+x} )]

Which can be solved via Newton-Raphson or a solver software, in this case, I will provide you the answer:

x=n_{Ag}=21.0molAg

So the mass is:

m_{Ag}=21.0mol*\frac{107.9g}{1mol}\\ \\m_{Ag}=2,265.9g

Best regards!

3 0
3 years ago
Balloon has a volume of 600-ml at temperature of 360 K. If the temperature of
Molodets [167]

Answer:

V₂ ≈416.7 mL

Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

  • V₁ / T₁ = V₂ / T₂

where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,

  • V₁= 600 mL
  • T₁= 360 K
  • T₂= 250 K

Substitute the values into the formula.

  • 600 mL /360 K = V₂ / 250 K

Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

  • 250 K * 600 mL /360 K = V₂ / 250 K * 250 K
  • 250 K * 600 mL/360 K = V₂

The units of Kelvin cancel, so we are left with the units of mL.

  • 250 * 600 mL/360=V₂
  • 416.666666667 mL= V₂

Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.

  • 416.7 mL ≈V₂

The volume of the balloon at 250 K is approximately 416.7 milliliters.

5 0
3 years ago
What is the main difference between a proton and a neutron?
Olenka [21]
I’m pretty sure it’s B since ones charge the neutral while ones is positive, it’s an obvious difference as well/
5 0
3 years ago
Read 2 more answers
Other questions:
  • What state of matter is achieved if a large amount of energy is added to a gas? vapor liquid plasma solid
    15·2 answers
  • What is produced during all combustion reactions?
    9·2 answers
  • Asprin is a compond with the molecular formula, C9H8O4. What is the percent composition?
    15·1 answer
  • 100 points! Please help me understand how to do this :)
    13·2 answers
  • Which state of matter is made up of electrically charged particles?
    13·2 answers
  • if you are working with a radioactive source emitting particles of several kinds all positively charged not necessarily of the s
    9·1 answer
  • Inner and outer plants
    11·2 answers
  • Explain why aluminum does not react with potassium nitrate (KNO3) although it reacts with copper nitrate.
    13·1 answer
  • Help Tell me the answer.
    6·1 answer
  • IS THISS RIGHTTTTT???
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!