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Studentka2010 [4]
3 years ago
10

A floating ice block is pushed through a displacement d = (23 m) i - (9 m) j along a straight embankment by rushing water, which

exerts a force F = (200 N) i - (149 N) j on the block. How much work does the force do on the block during the displacement?
Physics
2 answers:
musickatia [10]3 years ago
4 0

Answer:

Work done, W = 5941 joules

Explanation:

It is given that,

Force exerted on the block, F=(200i-149j)\ N

Displacement, x=(23i-9j)\ m

Let W is the work done by the force do on the block during the displacement. Its formula is given by :

W=F.d

W=(200i-149j){\cdot} (23i-9j)                    

Since, i.i = j.j = k.k = 1

W=4600+1341

W = 5941 joules

So, the work done by the force do on the block during the displacement is 5941 joules. Hence, this is the required solution.

Sav [38]3 years ago
3 0

Answer:

Work = 5941 J

Explanation:

As we know that work done is given by the equation

W = F. d

here we know that

F  = (200 N)\hat i - (149 N) \hat j

also we have

d = (23m) \hat i - (9 m)\hat j

now from above formula we have

W = (200 N\hat i - 149 N \hat j).(23 m\hat i - 9m \hat j)

W = 5941 J

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