frequency fapproach is heard by a passenger = 302.05 Hz
frequency frecede is heard by a passenger = 228.37433 Hz
Given :
speed of train to the ground = 30.0 m/s
frequency emitted by the train whistle = 262 Hz
speed of sound in air = 344 m/s
To Find :
(A) frequency fapproach (B) frequency frecede
Solution :
The frequency of approach is given by
f' = f <u>v + v(relative)</u>
v - v(air)
= 262x <u>344 + 18</u>
344 - 30
f' = 302.05 Hz
The frequency of approach is 302.05 Hz
The frequency of recede is given by
f' = f <u>v - v(relative)</u>
v + v(air)
= 262 x <u>344 - 18</u>
344 + 30
The frequency of recede is 228.37433 Hz
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