A train is traveling at 30.0 m/sm/s relative to the ground in still air. The frequency of the note emitted by the train whistle

Question

1 year ago

10

is 262 HzHz. The speed of sound in air should be taken as 344 m/sm/s .

1 answer:

vlada-n [284] · Answer 1 · 2023-03-16T08:01:03+03:00

frequency fapproach is heard by a passenger = 302.05 Hz

frequency frecede is heard by a passenger = 228.37433 Hz

Given :

speed of train to the ground = 30.0 m/s

frequency emitted by the train whistle = 262 Hz

speed of sound in air = 344 m/s

To Find :

(A) frequency fapproach (B) frequency frecede

Solution :

The frequency of approach is given by

f' = f v + v(relative)

v - v(air)

= 262x 344 + 18

344 - 30

f' = 302.05 Hz

The frequency of approach is 302.05 Hz

The frequency of recede is given by

f' = f v - v(relative)

v + v(air)

= 262 x 344 - 18

344 + 30

The frequency of recede is 228.37433 Hz

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