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bixtya [17]
3 years ago
12

The relationship among mass force and acceleration is explained by

Physics
2 answers:
Anettt [7]3 years ago
7 0
Newton's second law of motion. F = m a .
Murljashka [212]3 years ago
6 0
Newton's Second Law Of Motion:

Force = Mass x Acceleration

----

* Force, a product of mass and acceleration, is measured in Newtons. (N)
* Mass is the amount of matter an object contains. (kilograms)
* Acceleration is the increase in velocity over time, which is measured in metres per second squared. (m/s²)
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A 5.0 kg medicine ball and a 7.0 kg medicine ball are the same size and shape. If you were in outer space, how would you determi
Scrat [10]
Answer:
The objects can be distinguished by their weight instead of by mass.

Explanation
Because mass is constant, the two objects cannot be distinguished by mass.

However, gravitational acceleration varies in outer space. Therefore the heavier mass will register a higher reading on a weighing scale.

Note that an object of mass M weighs Mg, where g =  acceleration due to gravity.
5 0
3 years ago
A ball of mass m is thrown into the air in a 45° direction of the horizon, after 3 seconds the ball is seen in a direction 30° f
Rzqust [24]

Answer:

Velocity (magnitude) is 98.37 m/s

Explanation:

We use the vertical component of the initial velocity, which is:

v_{0y}=v_0*sin(45)=\frac{\sqrt{2} }{2}v_0

Using kinematics expression of vertical velocity (in y direction) for an accelerated motion (constant acceleration, which is gravity):

v_{y}=v_{0y}+a*t=\frac{\sqrt{2} }{2}v_0-9.8t

Now we need to find v_y as a function of v_0. We use the horizontal velocity, which is always the same as follow:

v_x=v_0cos(45\º)=\frac{\sqrt{2} }{2}v_0=v_{t=3}*cos(30\º) \\

We know the angle at 3 seconds:

v_y(t=3)=v_{t=3}*sin(30\º)\\v_{t=3}=\frac{v_y}{sin(30\º)}

Substitute  v_{t=3} in  v_x and then solve for  v_y

\frac{\sqrt{2} }{2}v_0=\frac{v_y*cos(30\º) }{sin(30\º)} \\v_y=\frac{\sqrt{6} }{6}v_0

With this expression we go back to the kinematic equation and solve it for initial speed

\frac{\sqrt{6} }{6} v_0 =\frac{\sqrt{2} }{2}v_0-29.4\\v_0(\frac{\sqrt{6}-3\sqrt{2}}{6} )=-29.4\\v_0=98.37 m/s

3 0
4 years ago
Which structure is part of the inner ear?
ValentinkaMS [17]

cochlea is part of the inner ear. have a great day my friend

8 0
3 years ago
Read 2 more answers
if an object is moving with a velocity of 25m/s, an acceleration of 5m/s and has a travel time of 5s, what is the final velocity
miv72 [106K]

V = at + V0

where v0 is the initial speed, a is the acceleration and t is the time.

So:

v = 5m/s^2*5s + 25m/s = 50 m/s

4 0
3 years ago
How much pressure is being exerted by blood cells that are applying 375N of force over 25.5m2 of your body’s blood vessels?
astra-53 [7]

Answer:

Pressure = 14.71N/m²

Explanation:

Given the following data;

Force = 375N

Area = 25.5m²

To find the pressure;

Pressure = force/area

Pressure = 375/25.5

Pressure = 14.71N/m²

Therefore, the amount of pressure that is being exerted by blood cells is 14.71 Newton per meter square.

5 0
3 years ago
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