Answer:
The four resonance structures of the phenoxide ion are shown in the image attached
The conjugate base of cyclohexanol has only one resonance contributor, while
the conjugate base of phenol has four resonance contributors.
Explanation:
In organic chemistry, it is known that structures are more stable if they possess more resonance contributors. The greater the number of contributing canonical structures, the more stable the organic specie. Since the phenoxide ion has four contributing canonical structures, it is quite much more stable than cyclohexanol having only one contributing structure to its conjugate base. Hence the PKa(acid dissociation constant) of phenol is lesser than that of cyclohexanol. The conjugate base of phenol is stabilized by resonance.
Answer:
Since KOH is a strong base, the solution completely ionizes into K+ and OH- when in water. The reaction KOH --> K+ + OH- takes place. The concentration of [ OH- ] can then be used to calculate the pOH of the solution. pH = 14 - pOH = 14 - 1.48 = 12.52
Explanation:
It is measured with a barometer
Answer:
D) 373 mm Hg.
Explanation:
We can solve this problem by keeping in mind<em> Dalton's law of partial pressures</em>, which states that the total pressure of a mixture of gases is equal to the sum of each gas' partial pressures. In other words, for this case:
- Total Pressure = Ne Pressure + CO₂ Pressure + O₂ Pressure + H₂ Pressure
- 1245 mm Hg = Ne Pressure + 145 mm Hg + 228 mm Hg + 499 mm Hg
The answer is option D) 373 mm Hg.