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2 years ago

Plz someone help, really struggling

Chemistry

1 answer:

frez [133]2 years ago

6 0

Answer:

22.9 Liters CO(g) needed

Explanation:

2CO(g) + O₂(g) => 2CO₂(g)

? Liters 32.65g

= 32.65g/32g/mol

= 1.02 moles O₂

Rxn ratio for CO to O₂ = 2 mole CO(g) to 1 mole O₂(g)

∴moles CO(g) needed = 2 x 1.02 moles CO(g) = 2.04 moles CO(g)

Conditions of standard equation* is STP (0°C & 1atm) => 1 mole any gas occupies 22.4 Liters.

∴Volume of CO(g) = 1.02mole x 22.4Liters/mole = 22.9 Liters CO(g) needed

___________________

*Standard Equation => molecular rxn balanced to smallest whole number ratio coefficients is assumed to be at STP conditions (0°C & 1atm).

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Alex17521 [72]

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