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3 years ago

BALANCE THE FOLLOWING EQUATION

Chemistry

1 answer:

Musya8 [376]3 years ago

4 0

Answer:

1) Sc(C2H3O2)3 + Na3BO3 = 3 NaC2H3O2 + ScBO3

2) 2 Ba3(PO4)2 + 3 Ca2SiO4 = 3 Ba2SiO4 + 2 Ca3(PO4)2

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Select the correct answer.

son4ous [18]

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7 0

3 years ago

An empty vial weighs 55.32 g.

ziro4ka [17]

The answer is: Volume of mercury = 9.63 $cm^3$ .

Density (d) is defined as mass of substance divided by its volume. Thus, if mass and density are known, then Volume can be determined.

What is the formula of volume in terms of density?

Let mass of substance be 'm' and volume be 'V'. Thus, as per the definition of density, it is expressed as-

$d =\frac{m}{V}$

Thus, volume can be expressed as-

$V = \frac{m}{d}$

Now, mass of empty vial= 55.32 g and the mass of (vial+ mercury) = 185.56 g.

Thus, mass of mercury = $185.56\ g- 55.32\g = 130.24\ g$

Thus, mass of mercury = 130.24 g and density of mercury = $13.53\ g/cm^3$ . Its volume is calculated as-

$V =\frac{130.24\ g}{13.53\ g/cm^3} = 9.63\ cm^3$

Hence, volume of mercury = 9.63 $cm^3$ .

To learn more about Density and Volume, visit:

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7 0

1 year ago

What happens when the wire in an electromagnet is wrapped around a soft iron core?

Gre4nikov [31]

im not sure about this one but i think the field is spread out

4 0

3 years ago

Read 2 more answers

If oxygen has a molar mass of 16.0 g/mole, carbon has a molar mass of 12.0 g/mole and hydrogen has a molar mass of 1.01 g/mole,

Stolb23 [73]

The number of mole of ethanol present in the beaker is 0.217 mole

Description of mole
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass

How to determine the mole of C₂H₅OH
From the question given above, the following data were obtained:
Mass of C₂H₅OH = 10 g
Molar mass of C₂H₅OH = (12×2) + (1.01×5) + 16 + 1.01 = 46.06 g/mol
Mole of C₂H₅OH =?

Mole = mass / molar mass
Mole of C₂H₅OH = 10 / 46.06
Mole of C₂H₅OH = 0.217 mole

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5 0

2 years ago

Which of these compounds would you expect

Veseljchak [2.6K]

ClBr, two nonmetals

Hope this helps you

6 0

2 years ago