Answer:
The right option is B
Explanation:
The frequency of the wave is given by the following formula:

where,
f = frequency of the wave.
c = speed of the light.
λ = wavelength of the light.



Therefore the correct option is B.
Answer:
a) 2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂
b) Ni(OH)₂
c) KOH
d) 0.927 g
e) K⁺=0.067 M, SO₄²⁻=0.1 M, Ni²⁺=0.067 M
Explanation:
a) The equation is:
2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂ (1)
b) The precipitate formed is Ni(OH)₂
c) The limiting reactant is:


From equation (1) we have that 2 moles of KOH react with 1 mol of NiSO₄, so the number of moles of KOH is:
Hence, the limiting reactant is KOH.
d) The mass of the precipitate formed is:
e) The concentration of the SO₄²⁻, K⁺, and Ni²⁺ ions are:


I hope it helps you!
Answer:
C. The ability to release tremendous amounts of energy
Explanation:
The decay of massive and unstable nuclei which leads to the formation of newer atoms or nuclei accompanied by the release of energy is known as nuclear fission. In a splitting reaction such as fission, energy is released from the conversion of mass.
The energy released in a fission reaction can be used to generate electricity through a series of process. Most advanced countries in the world generates their electricity through this process.
Answer:
Th is the symbol for element Thorium.
Mg is magnesium while Mg 2+ is magnesium Ion. Judging from periodic trends, atomic radius is one half the distance between the atoms of two covalently bonded atoms. It decreases as elevtrons are added to valence shells. That means, across the period it increases and down the group it decreases. Making Mg2+ smaller.
Electronegativity is the energy needed to take an electron in the gaseous state. Florine is more electron negative that lithium. It increases across the period and decreases down the group. Except in the Noble group.
Explanation:
Answer:
<h2>225 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula

m is the mass
v is the velocity
From the question we have

We have the final answer as
<h3>225 J</h3>
Hope this helps you