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4 years ago

How many carbon atoms enter the electron transport chain per glucose molecule?

Chemistry

2 answers:

Len [333]4 years ago

7 0

Zero, the Krebs Cycle converts them all to CO2 which is released.

expeople1 [14]4 years ago

6 0

NO carbons from glucose enter the electron transport chain.The Krebs cycle reactions convert all of them to carbon dioxide, which is released. In Krebs cycle both of the pyruvate molecules get converted into NADPHs and FADHs. In the electron transport chain, each molecule of NADPH produce 3 molecules of ATP and each FADH molecule produce 2 molecules of ATP. In the Glycolysis (consume 2 ATPs and produce 4 ATPs) and Krebs cycle we produce 4 ATPs, 10 NADHs, and 2 FADHs . So at the end we have 38 molecules of ATP . As two were consumed in Glycolysis so we have 36 ATPs net .

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Compute the molar enthalpy of combustion of glucose (C6 H12O6 ): C6 H12O6 (s) + 6 O2 (g) → 6 CO2 (g) + 6 H2 O (g) Given that com

lana66690 [7]

Answer:

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

Explanation:

Step 1: Data given

Mass of glucose = 0.305 grams

Combustion of 0.305 grams causes a raise of 6.30 °C

Calorimeter has a heat capacity of 755 J/°C

Molar mass of glucose = 180.2 g/mol

Step 2: The balanced equation

C6H12O6 (s) + 6O2 (g) → 6CO2 (g) + 6H2O (g)

Step 3:

ΔH = (m * C * ΔT + c(calorimeter) * ΔT)

with m = mass of the solutin = 0.305 grams

with C = heat capacity of water = 4.184 J/g°C

with ΔT = the change in temperature = 6.30 °C

with c(calorimeter) = 755 J/°C

ΔH = 0.305 * 4.184 *6.30 + 755 * 6.30 = 4764.5 J ( negative because it's exothermic)

Step 4: Calculate moles of glucose

Moles glucose = mass glucose / Molar mass glucose

Moles glucose = 0.305 grams / 180.2 g/mol

Moles glucose = 0.00169 moles

Step 5: Calculate molar enthalpy

Molar enthalpy = -4764.5 J / 0.00169 moles

Molar enthalpy = - 2819254.2 J/moles = -2819.3 kJ/moles

The molar enthalpy of combustion of glucose is -2819.3 kJ/mol

5 0

3 years ago

An aluminum block has a mass of 82.0 g and a volume of 12.8 cm3. what is the block's density to the nearest g/cm3?

aksik [14]

Density is mass over volume. If you put it into a formula it would look like this:

$D = \frac{m}{v}$

Based on the problem given, you can see that the mass of the aluminum block is 82.0 g and the volume is 12.8 cm3. Just put that into your equation and solve for it:

$D = \frac{m}{V}= \frac{82.0g}{12.8cm^{3} } = 6.4g/ cm^{3}$

The answer is then letter C.

6 0

4 years ago

A potential energy diagram is shown. A graph is plotted with Potential Energy in KJ on the y axis and Reaction Pathway on the x

Leya [2.2K]

Answer:

NOT A

Explanation:

3 0

4 years ago

Ca(OH)2(aq)+HNO3(aq)→H2O(l)+Ca(NO3)2(aq)

shtirl [24]

what are we doing in that question

Explanation:

I dunno know

6 0

3 years ago

. How many grams of H2O can you make with 120g of O2.

Sladkaya [172]

Answer:

i don't thing i understand the question.

Explanation:

7 0

3 years ago