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Horizontal angulation is: Select one: a. the side-to-side angulation. b. different when using the paralleling and bisecting tech

statuscvo [17]

Horizontal angulation is Select one: a. the side-to-side angulation. b. different when using the paralleling and bisecting techniques.

Angles that are horizontal. relates to the central ray's placement in a horizontal, or side-to-side, plane.

A picture with an overlap of nearby structures in the horizontal plane is produced by situating the central ray such that the horizontal angulation is not directed through the interproximal contacts of the adjacent teeth (the contact areas of the teeth are superimposed over each other).

Fracture angulation refers to a particular kind of fracture displacement in which the bone's natural axis has been changed so that the distal end now points off in a different direction. When using a bite-wing tab, the x-ray beam's center ray must be pointed at the contact points between teeth. The x-ray beam must be centered on the receptor to guarantee that the receptor is exposed.

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8 0

2 years ago

1. horizontal row in the periodic table____ 2. vertical column in the periodic table____ 3. A repetition of properties occurs wh

Anna11 [10]

Answer:

1. Periods

2. Groups of families

3. the statement is true about Periodic law

4. metals

5.transition metals

6.atomic radius

7. cations

8. electrons

9. electronegativity of the atom

10. ionization energy

Explanation:

1. horizontal row in the periodic table____are called Periods

2. vertical column in the periodic table____ are called Groups of families

3. A repetition of properties occurs when elements are arranged in order of increasing atomic number.____ True about Periodic Law (most elements that fall within the same families has similar properties)

4. type of element that is a good conductor of heat and electric current____ are metals that are found in group 1 and 2 of the periodic table Boron, tin, silver, Zinc, Alluminium, Germanium, Pollonium, antimony, e.t.c

5. type of element characterized by the presence of electrons in the dorbital____are called transition metals

6. one-half the distance between the nuclei of two atoms when the atoms are joined____ are called atomic radius

7. type of ion formed by Group 2A elements____are Cations

8. subatomic particles that are transferred to form positive and negative ions____ are called electrons

9. ability of an atom to attract electrons when the atom is in a compound____ is called electronegativity of the atom

10. energy required to remove an electron from an atom is called ionization energy

4 0

4 years ago

Two protons move with uniform circular motion in the presence of uniform magnetic fields. Proton one moves twice as fast as prot

lubasha [3.4K]

Answer:

r₂ = 4 r

Explanation:

For this exercise let's use Newton's second law with the magnetic force

F = q v x B

bold letters indicate vectors, the magnitude of this expression is

F = q v B sin θ

in this case we assume that the angle is 90º between the speed and the magnetic field.

If we use the rule of the right hand with the positive charge, the thumb in the direction of the speed, the fingers extended in the direction of the magnetic field, the palm points in the direction of the force, which is towards the center of the circle, therefore the force is radial and the acceleration is centripetal

a = v² / r

let's use Newton's second law

F = ma

q v B = m v² / r

r = $\frac{qB}{mv}$

Let's apply this expression to our case.

Proton 1

r = \frac{qB_1}{mv_1}

Proton 2

r₂ = $\frac{q \ B_2}{m \ v_2}$

in the exercise indicate some relationships between the two protons

* v₁ = 2 v₂

v₂ = v₁ / 2

* B₂ = 2B₁

we substitute

r₂ = $\frac{q \ 2B_1}{m \ \frac{v_1}{2} }$

r₂ = 4 $\frac{qB_1}{mv_1}$

r₂ = 4 r

7 0

3 years ago

How long is a pendulum with a period of 1.0 S on the moon which has 1/6 of the earths gravity

k0ka [10]

For small deflections, T = 2*pi*sqrt(L / g) where T is period, L is length and g is gravity. Setting the equations to the same period, 2*pi*sqrt(3.85 / g) = 2*pi*(L / (1/6 * g)) The equation reduces to 3.85 m = 6 * L so L = 0.642 m chrsclrk · 7 years ago

7 0

3 years ago

The hindenburg zeppelin contained 200,000 m^3 of hydrogen, with a density of 0.0899 kg/m^3. What is the mass of the hydrogen?

oksian1 [2.3K]

d=m/v

0.0899=m/200000

or,0.0899*200000=m

m=17980

6 0

3 years ago

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