Step-by-step explanation:
If you know, the sine. You must find the cos ratio, using the Pythagorean trig theorem.
Next, you use the half angle identity for sin

Example.

We must find

First, use the Pythagorean identity





Now use the half angle identiy




So the answer for our example is 1/2
It would be 1080
Just use a calculator
Answer:
a: 12
b: as much as what?
c: 70
d: 10 times as much
Step-by-step explanation:
a: 4 * 3 = 12
c: 700 / 10 = 70
d: 800 * 10 = 8000
It would be 12.5 square miles I would appreciate the Brainliest
Answer:
5secs
Step-by-step explanation:
Given the equation of the height expressed ad;
h(t) = - 16t^2 + initial height
Given that initial height = 400feet
h(t) = - 16t^2 + 400
The waste will hit the ground at when h(t) = 0
substitute
0 = - 16t^2 + 400
16t^2 = 400
t² = 400/16
t² = 25
t = √25
t = 5secs
Hence it will take the easte 5secs to hit the ground