Having 23.26 g of NaOH and 18.73 g of HCl what will be the limiting reactant
1 answer:
NaOH + HCl => NaCl + H2O
1 mol of NaOH react with 1 mol of HCL
The molecular mass of NaOH is 39.997
The molecular mass of HCl is 36.46
Moles of HCl
=18.73/36.46
=0.5137
Mole of NaOH
=23.26/39.997
=0.5815
moles of NaOH >moles of HCl
so there are not enough HCl
the answer is HCl
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Is that high school stuff or college?
The answer to this is solved through stochiometry: the answer is this: 0.0833mol