What is the product of an addition reaction between butanal, ch3−ch2−ch2−cho, and water?
1 answer:
We have to get the product of the addition reaction between butanal and water.
The product of the addition reaction between butanal and water is the gem di-ol which is unstable and it produces the reactant i.e. butanal only.
The reaction is shown in the figure.
From the figure we can see that in the addition reaction there the –C atom of the –CHO (aldehyde group) possess two –OH (hydroxyl group) as a product (gem-diol) of addition reaction, which is highly unstable and water molecule are regenerate to form the reactant i.e. butanal again.
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Answer:
92.37°C
Explanation:
Assuming the volume remains the same in both the states ( bicycle tire).
Then as per ideal gas equation
where P1, P2 are pressure at two different states and T1, T2 are temperature at these two states
Given:
P1 = 1.34 atm, T1 = 33.0 ° C = 306K
P2 = 1.60 atm, T2 = ?
1.34/306 = 1.60/T_2
⇒ T2 = 1.60×306/1.34
= T2= 365.37K= 92.37°C