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ivanzaharov [21]
3 years ago
5

If 60.2 grams of hg combines completely with 24.0 grams of br to form a compound what is the percent

Chemistry
2 answers:
GarryVolchara [31]3 years ago
7 0

The percentage composition of Hg in the given compound is \boxed{71.5{\text{ \% }}}.

Further explanation:

The amount of substance that is present in any mixture is known as concentration. It is expressed in different forms, called as concentration terms. Most of the commonly used concentration terms are as follows:

1. Molality

2. Mole fraction

3. Molarity

4. Parts per million

5. Mass percent

6. Volume percent

7. Percentage composition

The given reaction occurs as follows:

 {\text{Hg}} + {\text{B}}{{\text{r}}_2} \to {\text{HgB}}{{\text{r}}_{\text{2}}}

The formula to calculate the percentage composition of Hg is as follows:

{\text{Percentage composition of Hg}} = \left( {\dfrac{{{\text{Mass of Hg}}}}{{{\text{Mass of HgB}}{{\text{r}}_2}}}} \right){\text{100 \% }}  …… (1)                                    

The formula to calculate the mass of {\text{HgB}}{{\text{r}}_{\text{2}}}  is as follows:

{\text{Mass of HgB}}{{\text{r}}_{\text{2}}} = {\text{Mass of Hg}} + {\text{Mass of B}}{{\text{r}}_{\text{2}}}       …… (2)                                                      

The mass of Hg is 60.2 g.

The mass of {\text{B}}{{\text{r}}_{\text{2}}} is 24 g.

Substitute these values in equation (2).

\begin{aligned}{\text{Mass of HgB}}{{\text{r}}_{\text{2}}} &= 60.2{\text{ g}} + {\text{24 gAC}}\\&= {\text{84}}{\text{.2 g}}\\\end{aligned}  

The mass of Hg is 60.2 g.

The mass of {\text{HgB}}{{\text{r}}_{\text{2}}} is 84.2 g.

Substitute these values in equation (1).

 \begin{aligned}{\text{Percentage composition of Hg}} &= \left( {\frac{{{\text{60}}{\text{.2 g}}}}{{{\text{84}}{\text{.2 g}}}}} \right){\text{100 \% }}\\&= {\text{71}}{\text{.49 \% }}\\&\approx {\text{71}}{\text{.5 \% }}\\\end{aligned}

Therefore the percentage composition of Hg in the compound is 71.5 %.

Learn more:

  1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: brainly.com/question/3064603
  2. What is the concentration of alcohol in terms of molarity? brainly.com/question/9013318

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Concentration terms

Keywords: Hg, Br2, HgBr2, 60.2 g, 24 g, 84.2 g, mass of Hg, mass of Br2, mass of HgBr2, 71.5 %, concentration terms, molality, molarity, mole fraction, percentage composition.

NikAS [45]3 years ago
6 0

Answer is: the percent composition of Hg in the compound is 71.5%.

Balanced chemical reaction: Hg + Br₂ → HgBr₂.

m(Hg) = 60.2 g; mass of the mercury.

m(Br₂) = 24.0; mass of the bromine.

m(HgBr₂) = m(Hg) + m(Br₂).

m(HgBr₂) = 60.2 g + 24 g.

m(HgBr₂) = 84.2 g; mass of the compound.

ω(Hg) = m(Hg) ÷ m(HgBr₂) · 100%.

ω(Hg) = 60.2 g ÷ 84.2 g · 100%.

ω(Hg) = 71.5%.

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The sample of lithium occupies the largest volume.

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Given the densities for the four elements, we have the expression d=\frac{m}{V} that shows the relationship between mass and Volume to express the density of an element.

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d_{lithium}=\frac{m_{lithium}}{V_{lithium}}=0.53g/mL

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d_{aluminum}=\frac{m_{aluminum}}{V_{aluminum}}=2.70g/mL

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The problem says that all the samples have the same mass, so:

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Now, solving for the Volume in each element and with m as a constant, we have:

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V_{aluminum}=\frac{m}{d_{aluminum}}

V_{aluminum}=\frac{1}{2.70\frac{g}{mL}} *m

V_{aluminum}=3.70*10^{-1}\frac{mL}{g}*m

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So we can see that the sample of lithium occupies the largest volume with 1.88mL

Note that m only can take positive values, so if you change the value of m, always will be the lithium which occupies the largest volume.

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