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rewona [7]
3 years ago
6

State the mathematical expression to define the availability of equipment over a specified time and operational availability?

Engineering
1 answer:
Gelneren [198K]3 years ago
7 0

Answer:

Availability=\dfrac{Up\ time}{Down\ time+Up\ time}

Explanation:

Availability:

  It define as the probability of system which perform desired task before showing any failure .

The availability can be define as follows

 Availability=\dfrac{Up\ time}{Down\ time+Up\ time}

Or we can say that

Availability=\dfrac{Up\ time}{total\ time}

Availability can also be express as

 Availability=\dfrac{MTBF}{MTBF+MTTR}

Where MTBF is the mean time between two failure.

MTTR is the mean time to repair.

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1. A drawing of a cabinet shows that its dimensions are 9cm. by 4cm. The drawing indicates 1:50 scaling. What are the actual dim
yanalaym [24]

Explanation:

This means that for every 1 cm on the drawing, there is 80 cm in reality. To put it another way, take this

1:80 means that the building is 80 times the size of the drawing

80:1 means that the drawing is 80 times the size of the building

If it were 80:1, the drawing itself would be over 100m long.

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3 years ago
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Explanation:

4 0
3 years ago
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5) A 80-kg man has a total foot imprint area of 480 cm2. Determine the pressure this man exerts on the ground if (a) he stands o
attashe74 [19]

Answer:

The pressure exerted by this man on ground

(a) if he stands on both feet is 8.17 KPa

(b) if he stands on one foot is 16.33 KPa

Explanation:

(a)

When the man stand on both feet, the weight of his body is uniformly distributed around the foot imprint of both feet. Thus, total area in this case will be:

Area = A = 2 x 480 cm²

A = 960 cm²

A = 0.096 m²

The force exerted by man on his area will be equal to his weight.

Force = F = Weight

F = mg

F = (80 kg)(9.8 m/s²)

F = 784 N

Now, the pressure exerted by man on ground will be:

Pressure = P = F/A

P = 784 N/0.096 m²

<u>P = 8166.67 Pa = 8.17 KPa</u>

(b)

When the man stand on one foot, the weight of his body is uniformly distributed around the foot imprint of that foot only. Thus, total area in this case will be:

Area = A = 480 cm²

A = 0.048 m²

The force exerted by man on his area will be equal to his weight, in this case, as well.

Force = F = Weight

F = mg

F = (80 kg)(9.8 m/s²)

F = 784 N

Now, the pressure exerted by man on ground will be:

Pressure = P = F/A

P = 784 N/0.048 m²

<u>P = 16333.33 Pa = 16.33 KPa</u>

4 0
3 years ago
while performing a running compression test how should running compression compare to static compression
algol [13]

Answer:

The idle speed of a running compression should be between 50-75 PSI and that is about half of the static compression.

Explanation:

The Running or Dynamic compression is used to determine how well the cylinder in an engine  is absorbing air, reserving it for the proper length of time, and releasing it to the exhaust. The static or cranking compression test is used to check the sealing of the cylinder. Before performing the running compression test, the static compression test is first performed to rule out other issues like bent valves.

The standard value for the static compression is given by;

Compression ratio * 14.7 = Manufacturers Specification

The running compression should always be half of the static compression.

5 0
2 years ago
The air in a room has a pressure of 1 atm, a dry-bulb temperature of 24C, and a wet-bulb temperature of 17C. Using the psychrome
TEA [102]

Answer:

(a) Relative Humidity = 48%,

Specific humidity = 0.0095

(b) Enthalpy = 65 KJ/Kg of dry sir

Specific volume = 0.86 m^3/Kg of dry air

(c/d) 12.78 degree C

(e) Specific volume = 0.86 m^3/Kg of dry air

8 0
3 years ago
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