Answer:
V₂ = 20 V
Vt = 20 V
V₁ = 20 V
V₃ = 20 V
I₁ = 10 mA
I₃ = 3.33 mA
It = 18.33 mA
Rt = 1090.91 Ω
Pt = 0.367 W
P₁ = 0.2 W
P₂ = 0.1 W
P₃ = 0.067 W
Explanation:
Part of the picture is cut off. I assume there is a voltage source Vt there?
First, use Ohm's law to find V₂.
V = IR
V₂ = (0.005 A) (4000 Ω)
V₂ = 20 V
R₁ and R₃ are in parallel with R₂ and the voltage source Vt. That means V₁ = V₂ = V₃ = Vt.
V₁ = 20 V
V₃ = 20 V
Vt = 20 V
Now we can use Ohm's law again to find I₁ and I₃.
V = IR
I = V/R
I₁ = (20 V) / (2000 Ω)
I₁ = 0.01 A = 10 mA
I₃ = (20 V) / (6000 Ω)
I₃ = 0.00333 A = 3.33 mA
The current It passing through Vt is the sum of the currents in each branch.
It = I₁ + I₂ + I₃
It = 10 mA + 5 mA + 3.33 mA
It = 18.33 mA
The total resistance is the resistance of the parallel resistors:
1/Rt = 1/R₁ + 1/R₂ + 1/R₃
1/Rt = 1/2000 + 1/4000 + 1/6000
Rt = 1090.91 Ω
Finally, the power is simply each voltage times the corresponding current.
P = IV
Pt = (0.01833 A) (20 V)
Pt = 0.367 W
P₁ = (0.010 A) (20 V)
P₁ = 0.2 W
P₂ = (0.005 A) (20 V)
P₂ = 0.1 W
P₃ = (0.00333 A) (20 V)
P₃ = 0.067 W
Answer:
Option A (energy transformations) is the correct solution.
Explanation:
- Energy has become a local matter that has been primarily described as the commitment to deal as well as to generate heat. There are several other power sources, which can either be transferred or transformed to several other renewable technologies.
- This same fundamental law defined that the energy required including its universe has been corrected and therefore that energy is being generated as well as severely damaged but should only be moved from one location to the next.
Those certain possibilities are not connected to the circumstance in question. And therefore this answer seems to be the correct one.
Answer:

Explanation:
Initial speed of the mobile = 3.2 m/s
Final speed of the mobile = 5.2 m/s
Time, t = 8 s
We need to find the acceleration of the mobile. It can be given by the change in velocity divided by time. So,

So, the acceleration of the mobile is
.
Answer:
Matlab code with step by step explanation and output results are given below
Explanation:
We have to construct a Matlab function that creates a row vector "countValues" with elements 1 to endValue. That means it starts from 1 and ends at the value provided by the user (endValue).
function countValues = CreateArray(endValue)
% Here we construct a row vector countValues from 1:endValue
countValues = 1:endValue;
% then we transpose this row vector into column vector
countValues = countValues';
end
Output:
Calling this function with the endValue=11 returns following output
CreateArray(11)
ans =
1
2
3
4
5
6
7
8
9
10
11
Hence the function works correctly. It creates a row vector then transposes it and makes it a column vector.