Just trying to personally understand this is making me shed a few tears. Good luck with finding someone to answer your question!
Answer: (B) 100
Explanation:
Given that;
Pstatic = 20 psig , hz = 160ft, hf = 20ft
Now total head will be;
T.h = hz + hf
T.h= 160 + 20
T.h = 180ft
Minimum pressure = Psatic + egh
we know that specific weight of water is 62.4 (lb/ft3)
so
P.min = (20 bf/in² ) + (62.4 b/ft³ × 180 fr
P.min = (20 bf/in² ) + ( 62.4 × 180 × 1 ft²/144 in²)
P.min = 20 + 78
P.min = 98 lbf/in²
Therefore the minimum pressure rating (psi) of the piping system is most nearly B) 100
Answer:
import java.io.*;
import java.util.Scanner;
public class CountWordsInFile {
public static void main(String[] args) throws IOException {
Scanner keyboard = new Scanner(System.in);
System.out.print("Enter file name: ");
String fileName = keyboard.next();
File file = new File(fileName);
try {
Scanner scan = new Scanner(file);
int count = 0;
while(scan.hasNext()) {
scan.next();
count += 1;
}
scan.close();
System.out.println("Number of words: "+count);
} catch (FileNotFoundException e) {
System.out.println("File " + file.getName() + " not present ");
System.exit(0);
}
}
}
I’m thinking it would be c sorry if it’s wrong .
Answer:
coupling is in tension
Force = -244.81 N
Explanation:
Diameter of Hose ( D1 ) = 35 mm
Diameter of nozzle ( D2 ) = 25 mm
water gage pressure in hose = 510 kPa
stream leaving the nozzle is uniform
exit speed and pressure = 32 m/s and atmospheric
<u>Determine the force transmitted by the coupling between the nozzle and hose </u>
attached below is the remaining part of the detailed solution
Inlet velocity ( V1 ) = V2 ( D2/D1 )^2
= 32 ( 25 / 35 )^2
= 16.33 m/s
